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iris [78.8K]
3 years ago
8

A rectangle has an area of 24 cm2 Function f gives the length of the rectangle, in centimeters, when the width is w cm. Determin

e if each value, in centimeters, is a possible input of the function. A 0.5 B 48 C 0 D -6 E 3 0.5 0.5
Mathematics
2 answers:
levacccp [35]3 years ago
5 0

Answer:

Input is the value of w and the function f = 24/w as length x breadth = area of rectangle

If w = 0.5, then f = 24/0.5 = 48cm. So, it is a possible input of the function.

If w = 48, then f = 24/48 = 0.5cm. So, it is a possible input of the function.

If w = 0, then f = 24/0 = 0cm. So, it is not a possible input of the function as it cannot be defined

If w = -6, then f = 24/-6= -4cm. So, it is not a possible input of the function as a length and width can't be negative

If w = 3, then f = 24/3 = 8cm. So, it is a possible input of the function.

matrenka [14]3 years ago
4 0

Answer:

A. 3,  B. 0.5, & C.48

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Anon25 [30]

Answer:

The first one is equivalent [the 6x+48 = 2(3x+24)] and the second one is <u>NOT</u> equivalent [the 7x+21 ≠ 2(5x+3)]

Step-by-step explanation:

Just follow distributive property to solve these. You can ignore the first expression in both until you have to compare the answers.

1. 6x+48 and 2(3x+24)

2(3x+24) ---> 2(3x) + 2(24) ---> <u>6x + 48</u>

Bring in the first expression ~ <u>6x+48 and 6x+48 </u>

They are the same, so they are equivalent

2. 7x+21 and 2(5x+3)

2(5x+3) ---> 2(5x) + 2(3) ----> 10x + 6

Bring in the first expression ~ <u>7x+21 and 10x + 6</u>

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3 years ago
X+10=1/3(5x+10)<br><br> How do you solve this equation?
Nikitich [7]

Answer:

x = 10

Step-by-step explanation:

First, subtract 10 from both sides

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Then, subtract 5/3x from both sides

After, simplify


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Then finally simplify for your final answer of x = 10


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2 years ago
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ZanzabumX [31]

Answer: i think the answer is 2

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The standard form is called the scientific notation expressed generally as;

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Given the decimal value 98.704, we ill shift the decimal point to the back once to have;

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