Given:
6/7(7/6z)
First, you would have to multiply both fractions together:
6/7(7/6z) = 42/42z
Next, simplify:
1z
(Since 42/42 is a bit redundant, you would then simplify to 1z)
Finally, you can either leave the answer as 1z or you can just leave it as z, because in math, variables have an imaginary 1 in front of them so the 1 is not necessary.
Answer: z
I hope this helps!
Ok baby mommy wiwowiw i wi we eowowiwwill everything eis e
Answer:
m∠W = 125°
m∠X = 55°
m∠Z = 55°
Step-by-step explanation:
The shape is parallelogram WXYZ. m∠Y = 125.
A parallelogram is a quadrilateral shape in which both opposite sides and opposite angles are equal to each other. The diagonals of a parallelogram bisect each other. Also consecutive angles in a parallelogram are supplementary.
Therefore in parallelogram WXYZ:
m∠Z + m∠Y = 180° (Consecutive angles in a parallelogram are supplementary)
m∠Z + 125 = 180
m∠Z = 180 - 125
m∠Z = 55°
m∠W = m∠Y (Opposite angles are equal)
m∠W = 125°
m∠W + m∠X = 180° (Consecutive angles in a parallelogram are supplementary)
m∠X + 125 = 180
m∠X = 180 - 125
m∠X = 55°
Answer:
The beam will bend by 50 mm with a mass of 100kg?
Step-by-step explanation:
The first step in solving the problem of direct variation is setting up the relation mathematically.
We can do this as follows:
The bending of the beam varies directly as its mass.
![20 \alpha 40kg](https://tex.z-dn.net/?f=20%20%20%5Calpha%20%2040kg)
here is the symbol representing direct variation. To remove this and replace it with an equality sign, we have to introduce a constant of proportionality, k
![20 = k \times 40](https://tex.z-dn.net/?f=20%20%3D%20k%20%5Ctimes%2040)
k = 20 /40 = 0.5
We can now use this to find the distance the beam will bend with a mass of 100kg?
This will be
![Bending = 0.5 \times 100 =50mm](https://tex.z-dn.net/?f=Bending%20%3D%200.5%20%5Ctimes%20100%20%3D50mm)
There fore, the beam will bend by 50 mm with a mass of 100kg?
Hi, do you have a specific question with fractions to work on?