Answer:
ASA
Step-by-step explanation:
You can show the angles at either end of segment BC in triangles MBC and LCB are congruent, so you have two angles and the segment between. The appropriate theorem in such a case is ASA.
Answer:
49.7%
Step-by-step explanation:
A cdircle is located within a square.
<u>Area of the circle</u>
Area = 
, where r = 4 units.
Area Circle = 50.3 units^2
<u>Area of the square</u>
Area = l*w or l^2 for a square, since l = w
Area = (10 units)^2
Area = 100 units^2
<u>Area in the square but outside the circle</u>
This is the difference [Square minus Circle Areas]
Square minus Circle Areas = 100 - 50.3 or <u>49.7 units^2</u>
<u>Probability</u>
The probability of picking a point in the square that is not in the circle is the ration of the two areas: <u>[Outside Circle/Square]x100%</u>
<u></u>
<u>(</u>49.7 units^2)/(100 units^2)x100% = 49.7%
<u></u>
Answer:
The correct option is:
h = 1, k = 16
Step-by-step explanation:
y=4x^2-8x+20 =0
It is a quadratic formula in standard form:
ax^2+bx+c
where a = 4 , b = -8 and c=20
The vertex form is:
a(x − h)2 + k = 0
h is the axis of symmetry and (h,k) is the vertex.
Calculate h according to the following formula:
h = -b/2a
h= -(-8)/2(4)
h = 8/8
h = 1
Substitute k for y and insert the value of h for x in the standard form:
ax^2+bx+c
k = 4(1)^2+(-8)(1)+20
k = 4-8+20
k=-4+20
k = 16
Thus the correct option is h=1, k=16....
Answer:
Step-by-step explanation:
You have to multiply 8 times 12 and that is 96
