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My name is Ann [436]
2 years ago
5

Choose the correct word that completes each statement about inscribing a square in a circle.

Mathematics
1 answer:
Anna11 [10]2 years ago
7 0

Answer:

1. Perpendicular

2. Isosceles

3. Never

Step-by-step explanation:

1. AC ⊥ BD because diameter of a square are perpendicular bisector of each other.

2. In Δ AOB , By using pythagoras : AB² = OA² + OB² .......( 1 )

In Δ COB , By using pythagoras : BC² = OC² + OB²  ..........( 2 )

But, OA = OC because both are radius of same circle

So, by using equations ( 1 ) and ( 2 ), We get AB = BC ≠ AC

⇒ ABC is a triangle having two equal sides so ABC is an isosceles triangle.

3. The side can never be equal to radius of circle because the side of the square will be chord for the circle and in a circle chord can never be equal to its radius


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What is 1/5 times 24 as estimate
Furkat [3]
 the  estimates or correct answer is 24/5 =4 4/5

4 0
3 years ago
Read 2 more answers
Divide the sum of 3/8 and -5/12 by the reciprocal of 16/27 x(-15)/8
Travka [436]

Answer:

First find the sum of 3/8 and -5/12

That is

3/8 - 5/12

First find the common denominator

The common denominator is 24

We get

3/8 - 5/12 = 3(3) - 5(2) / 24

= 9 - 10 / 24

= - 1 / 24

Next find the product of 16/27 x(-15)/8

That's

16/27 × -15/8

= -10/9

Next reverse -10/9

Which is -9/10

Next we divide it by = -1 /24

so we get

-1/24 ÷ -9/10

Change the sign to (×) and reverse the second fraction

We get

-1/24 × -10/9

= 5 / 108

Hope this helps

4 0
3 years ago
What is the arithmetic mean for the following numbers,88,80,75,70,38,45,70,60,60,50​
Natalija [7]

Answer:

63.6

Step-by-step explanation:

X=£fx/n

= 88+80+75+70+38+45+70+60+60+50/10

= 636/10

= 63.6

Mark me as Brainliest.

Please feel free to ask if you have any questions.

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5 0
2 years ago
I need help on this thank you ​
Rasek [7]
I think it B or D I hope i don’t get it wrong
5 0
3 years ago
In an arithmetic sequence, a17 = -40 and
Viktor [21]

Answer:

Tn = 2Tn-1 - Tn-2

Step-by-step explanation:

Before we can generate the recursive sequence, we need to find the nth term of the given sequence.

nth term of an AP is given as:

Tn = a+(n-1)d

If a17 = -40

T17 = a+(17-1)d = -40

a+16d = -40 ...(1)

If a28 = -73

T28 = a+(28-1)d = -73

a+27d = -73 ...(2)

Solving both equations simultaneously using elimination method.

Subtracting 1 from 2 we have:

27d - 16d = -73-(-40)

11d = -73+40

11d = -33

d = -3

Substituting d = -3 into 1

a+16(-3) = -40

a - 48 = -40

a = -40+48

a = 8

Given a = 8, d = -3, the nth term of the sequence will be

Tn = 8+(n-1) (-3)

Tn = 8+(-3n+3)

Tn = 8-3n+3

Tn = 11-3n

Given Tn = 11-3n and d = -3

Tn-1 = Tn - d... (3)

Tn-1 = 11-3n +3

Tn-1 = 14-3n

Tn-2 = Tn-2d...(4)

Tn-2 = 11-3n-2(-3)

Tn-2 = 11-3n+6

Tn-2 = 17-3n

From 3, d = Tn - Tn-1

From 4, d = (Tn - Tn-2)/2

Equating both common difference

(Tn - Tn-2)/2 = Tn - Tn-1

Tn - Tn-2 = 2(Tn - Tn-1)

Tn - Tn-2 = 2Tn-2Tn-1

2Tn-Tn = 2Tn-1 - Tn-2

Tn = 2Tn-1 - Tn-2

The recursive formula will be

Tn = 2Tn-1 - Tn-2

5 0
3 years ago
Read 2 more answers
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