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Ray Of Light [21]
3 years ago
8

I'm confused on this practice assignment

Mathematics
1 answer:
dolphi86 [110]3 years ago
4 0

Answer: y = |x+3|-2

Step-by-step explanation:

The answer is the second one, y = |x+3|-2

It's similar to Parabola, |x+3|-2 is just like (x+3)^2-2, except about the graph. So (-3,-2)

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0.9 x 100=<br>13.79 x 100=<br>29.894 x 100=<br>​
Vladimir [108]

Answer:

multiplying by 100 "shifts" decimal point to the right by 2

90  

1379  

2989.4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the value of this expression when c= -4 and d = 10?
Alisiya [41]

Answer:

c + d^2 = 96

Step-by-step explanation:

Given

c = -4\\d = 10

Required

Find c + d^2

To find c + d^2, we simply substitute 10 for d and -4 for c in the given expression.

The step is as follows:

c + d^2

Substitute c = -4\\d = 10

c + d^2 = -4 + 10^2

c + d^2 = -4 + 10*10

c + d^2 = -4 + 100

c + d^2 = 96

The expression cannot be solved any further; so, we can conclude that when d = 10 and c = -4, c + d^2 = 96

6 0
3 years ago
Which of the following is not an asymptote of the hyperbola xy = -42? y = 0 x = 0 y = x
Rainbow [258]

Given:

The equation of the hyperbola is:

xy=-42

To find:

The the equation which is not an asymptote of the hyperbola.

Solution:

We have,

xy=-42

It can be written as:

y=\dfrac{-42}{x}

Equating denominator and 0, we get

x=0

So, the vertical asymptotic is x=0.

The degree of numerator is 0 and the degree of denominator is 1.

Since the degree of numerator is greater that the degree of denominator, therefore the horizontal asymptote is y=0 and there is no oblique asymptote.

Therefore, y=x is not an asymptote of the given hyperbola and the correct option is C.

5 0
3 years ago
What type of triangle had side lengths of 4,7 and 9
Nina [5.8K]
A scaled triangle because they are all different lengths
4 0
3 years ago
A toy is accidentally dropped by a kid from his roof. The final velocity of the toy before it reached the ground was 8m/s. Find
jeka94

The height of the building is 3.27 m

Since the question described free-fall under gravity, we will be using the equation for fall under gravity.

Using v² = u² - 2gh where u = initial velocity of toy = 0 m/s (since it is falls from rest), v = final velocity of toy as it hits the ground = 8 m/s, g = acceleration due to gravity = 9.8 m/s² and h = distance the ball falls = height of building

So, making h subject of the formula, we have

h = -(v² - u²)/2g

Substituting the values of the variables into the equation, we have

h = -(v² - u²)/2g

h = -[(8 m/s)² - (0 m/s)²)/(2 × 9.8 m/s²)  

h = -(64 m²/s² - 0 m²/s²)/(2 × 9.8 m/s²)

h = -64 m²/s²/19.6 m/s²

h = -3.265 m

h ≅ -3.27 m

The value is negative since we take the top of the building as 0 m and downward direction as negative.

So, the height of the building is 3.27 m

Learn more about free fall here:

brainly.com/question/23180622

4 0
3 years ago
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