Question

A toy is accidentally dropped by a kid from his roof. The final velocity of the toy before it reached the ground was 8m/s. Find the height of the building. please solve this from which I could understand easily​

Answer 1

The height of the building is 3.27 m

Since the question described free-fall under gravity, we will be using the equation for fall under gravity.

Using v² = u² - 2gh where u = initial velocity of toy = 0 m/s (since it is falls from rest), v = final velocity of toy as it hits the ground = 8 m/s, g = acceleration due to gravity = 9.8 m/s² and h = distance the ball falls = height of building

So, making h subject of the formula, we have

h = -(v² - u²)/2g

Substituting the values of the variables into the equation, we have

h = -(v² - u²)/2g

h = -[(8 m/s)² - (0 m/s)²)/(2 × 9.8 m/s²)  

h = -(64 m²/s² - 0 m²/s²)/(2 × 9.8 m/s²)

h = -64 m²/s²/19.6 m/s²

h = -3.265 m

h ≅ -3.27 m

The value is negative since we take the top of the building as 0 m and downward direction as negative.

So, the height of the building is 3.27 m

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