The height of the building is 3.27 m
Since the question described free-fall under gravity, we will be using the equation for fall under gravity.
Using v² = u² - 2gh where u = initial velocity of toy = 0 m/s (since it is falls from rest), v = final velocity of toy as it hits the ground = 8 m/s, g = acceleration due to gravity = 9.8 m/s² and h = distance the ball falls = height of building
So, making h subject of the formula, we have
h = -(v² - u²)/2g
Substituting the values of the variables into the equation, we have
h = -(v² - u²)/2g
h = -[(8 m/s)² - (0 m/s)²)/(2 × 9.8 m/s²)
h = -(64 m²/s² - 0 m²/s²)/(2 × 9.8 m/s²)
h = -64 m²/s²/19.6 m/s²
h = -3.265 m
h ≅ -3.27 m
The value is negative since we take the top of the building as 0 m and downward direction as negative.
So, the height of the building is 3.27 m
Learn more about free fall here:
brainly.com/question/23180622
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