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sleet_krkn [62]
3 years ago
14

A soup bowl is in the shape of a hemisphere with a diameter of 10 cm. What is the approximate maximum volume of soup that the bo

wl can hold?
Mathematics
1 answer:
Oduvanchick [21]3 years ago
5 0

Answer:

3.48cm³ (approximated)

Step-by-step explanation:

The maximum water that bowl can hold = The volume of the bowl

\boxed{ \mathsf{volume \: of \: bowl =  \frac{2}{3}  \times \pi \: r {}^{3} }}

Radius is half of diameter.

<u>Given</u> -

  • Diameter = 10cm .

<em>From</em><em> </em><em>the</em><em> </em><em>given</em><em> </em><em>data</em><em> </em><em>we</em><em> </em><em>can</em><em> </em><em>derive </em><em>that</em><em> </em><em>the</em><em> </em><em>radius</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>hemispheri</em><em>cal</em><em> </em><em>bowl</em><em> </em><em>is</em><em> </em><em>5</em><em>c</em><em>m</em><em> </em><em>(</em><em>1</em><em>0</em><em>/</em><em>2</em><em>)</em>

Putting the known values into the formula to get the value of the volume of bowl :

\mathsf{volume =  \frac{2}{3} \times \:   3.14 \:  \times  {5}^{3} }

= 3.48888cm³

= 3.48cm³

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<h3 /><h3>What is Domain and range?</h3>

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