Question

A soup bowl is in the shape of a hemisphere with a diameter of 10 cm. What is the approximate maximum volume of soup that the bowl can hold?

Answer 1

Answer:

3.48cm³ (approximated)

Step-by-step explanation:

The maximum water that bowl can hold = The volume of the bowl

$\boxed{ \mathsf{volume \: of \: bowl = \frac{2}{3} \times \pi \: r {}^{3} }}$

Radius is half of diameter.

Given -

• Diameter = 10cm .

From the given data we can derive that the radius of the hemispherical bowl is 5cm (10/2)

Putting the known values into the formula to get the value of the volume of bowl :

$\mathsf{volume = \frac{2}{3} \times \: 3.14 \: \times {5}^{3} }$

= 3.48888cm³

= 3.48cm³