Answer:
The answer would be c
Step-by-step explanation:
The formula for volume is V=Bh where B is the area of the base.
plug in what they have given you:
600=B(15) you can divide both sides by 15
40=B We know that a cylinder's base is a circle so we can use the area f formula for a circle to solve for the radius.
40 = pi(r)^2 divide both sides by pi to get the r^2 alone
40/pi=r^2 square root both sides to get rid of the square
you should get
r=3.5 approximately
Answer:
a.![P(E_1/A)=0.0789](https://tex.z-dn.net/?f=P%28E_1%2FA%29%3D0.0789)
b.
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c.![P(E_3/A)=0.526](https://tex.z-dn.net/?f=P%28E_3%2FA%29%3D0.526)
Step-by-step explanation:
Let
are the events that denotes the good drive, medium drive and poor risk driver.
![P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20](https://tex.z-dn.net/?f=P%28E_1%29%3D0.30%2CP%28E_2%29%3D0.50%2CP%28E_3%29%3D0.20)
Let A be the event that denotes an accident.
![P(A/E_1)=0.01](https://tex.z-dn.net/?f=P%28A%2FE_1%29%3D0.01)
![P(A/E_2=0.03](https://tex.z-dn.net/?f=P%28A%2FE_2%3D0.03)
![P(A/E_3)=0.10](https://tex.z-dn.net/?f=P%28A%2FE_3%29%3D0.10)
The company sells Mr. Brophyan insurance policy and he has an accident.
a.We have to find the probability Mr.Brophy is a good driver
Bayes theorem,![P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}](https://tex.z-dn.net/?f=P%28E_i%2FA%29%3D%5Cfrac%7BP%28A%2FE_i%29%5Ccdot%20P%28E_1%29%7D%7B%5Csum_%7Bi%3D1%7D%5E%7Bi%3Dn%7DP%28A%2FE_i%29%5Ccdot%20P%28E_i%29%7D)
We have to find ![P(E_1/A)](https://tex.z-dn.net/?f=P%28E_1%2FA%29)
Using the Bayes theorem
![P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}](https://tex.z-dn.net/?f=P%28E_1%2FA%29%3D%5Cfrac%7BP%28A%2FE_1%29%5Ccdot%20P%28E_1%29%7D%7BP%28E_1%29%5Ccdot%20P%28A%2FE_1%29%2BP%28E_2%29P%28A%2FE_2%29%2BP%28E_3%29P%28A%2FE_3%29%7D)
Substitute the values then we get
![P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}](https://tex.z-dn.net/?f=P%28E_1%2FA%29%3D%5Cfrac%7B0.30%5Ctimes%200.01%7D%7B0.01%5Ctimes%200.30%2B0.50%5Ctimes%200.03%2B0.20%5Ctimes%200.10%7D)
![P(E_1/A)=0.0789](https://tex.z-dn.net/?f=P%28E_1%2FA%29%3D0.0789)
b.We have to find the probability Mr.Brophy is a medium driver
![P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395](https://tex.z-dn.net/?f=P%28E_2%2FA%29%3D%5Cfrac%7B0.03%5Ctimes%200.50%7D%7B0.038%7D%3D0.395)
c.We have to find the probability Mr.Brophy is a poor driver
![P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526](https://tex.z-dn.net/?f=P%28E_3%2FA%29%3D%5Cfrac%7B0.20%5Ctimes%200.10%7D%7B0.038%7D%3D0.526)
Can u take a picture please?
<h3>
Answer: (3, -1)</h3>
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Explanation:
The midpoint formula is ![(x_m, y_m) = \left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)](https://tex.z-dn.net/?f=%28x_m%2C%20y_m%29%20%3D%20%5Cleft%28%5Cfrac%7Bx_1%2Bx_2%7D%7B2%7D%2C%5Cfrac%7By_1%2By_2%7D%7B2%7D%5Cright%29)
This basically says to add the corresponding coordinates and divide by 2.
The given points (2,5) and (4,-7) have x coordinates of 2 and 4. They add to 2+4 = 6, and then that result cuts in half to 6/2 = 3. The x coordinate of the midpoint is 3.
The y coordinate of the midpoint is y = -1 since adding the y coordinates of the given points leads to 5+(-7) = -2 which cuts in half to -1.
So overall the midpoint is located at (3, -1)