Roberto's toy car travels at 40 centimeters per second (cm/sec) at high speed and 15 cm/sec at low speed. If the car travels for
15 seconds at high speed and then 30 seconds at low speed, what distance would the car have traveled?
2 answers:
Answer:
Step-by-step explanation:
15 seconds at high speed
1 sec = 40 cm
15 sec = 40 x 15
15 sec = 600 cm
30 seconds at low speed
1 sec = 15 cm
30 sec = 15 x 30
30 sec = 450 cm
Total distance = 600 + 450 = <u>1050 cm</u>
15 seconds at high speed
1 sec = 40 cm
15 sec = 40 x 15
15 sec = 600 cm
30 seconds at low speed
1 sec = 15 cm
30 sec = 15 x 30
30 sec = 450 cm
Total distance = 600 + 450 = 1050 cm
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Step-by-step explanation:
Answer:
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Step-by-step explanation:
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Answer:
5^4
Step-by-step explanation:
when dividing by powers subtract the denominator from the numerator
5-12 ÷(6-2)-1
Do whats in the parenthesis
5-12 ÷4-1
Do division next
5- 3- 1 = 1.
Do the same for the next.
(4-3) x 2+15 ÷(6-1)
1 x 2+15 ÷5
2+15÷5
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