The Volume is 192.5 cm3 so the last one
The first thing to is factor the denominator of the rational function:

to do this we'll need to find two number whose product is -3 and its sum is -2; those numbers are 1 and -3, so:

Now we can rewrite our rational function as follows:

Notice that we have a common factor (x-3) in both numerator and denominator; therefore we can cancel them:

Taking all the above into consideration we realize that x=3 is a removable discontinuity; the correct answer is the first one: there is a hole in x=3 and asymptote at x=-1.
Answer:
Step-by-step explanation:
Answer:
Option 1
Step-by-step explanation:
![\sqrt[4]{ {a}^{6} {b}^{4} {c}^{8} } \\ = {a}^{6 \div 4} {b}^{4 \div 4} {c}^{8 \div 4} \\ which \: gives \: option \: 1](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B%20%7Ba%7D%5E%7B6%7D%20%20%7Bb%7D%5E%7B4%7D%20%20%7Bc%7D%5E%7B8%7D%20%20%7D%20%5C%5C%20%20%20%3D%20%7Ba%7D%5E%7B6%20%20%5Cdiv%204%7D%20%20%7Bb%7D%5E%7B4%20%5Cdiv%204%7D%20%20%7Bc%7D%5E%7B8%20%5Cdiv%204%7D%20%5C%5C%20which%20%5C%3A%20gives%20%5C%3A%20option%20%5C%3A%201)
The x shows how they are meeting with the things to be with