Answer:
the probability that a randomly chosen test-taker will score 142 or lower = 0.8643
Step-by-step explanation:
We are given;
Data point; x = 142
Mean; μ = 153
Standard deviation; σ = 10
So,let's find the z-score using;
z = (x - μ)/σ
z = (142 - 153)/10
z = -1.1
From the z-distribution table attached, the probability is;
P(z < -1.1) = 1 - 0.13567 ≈ 0.8643
The only solution that I see is a=30x^2
Answer:
The longest bar in her histogram is the Intervals 5-9 with the value of 5
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached photo
My answer:
- Intervals 0-4 : there are 2 results
- Intervals 5-9 : there are 5 results
- Intervals 10-14 : there are 4 results
- Intervals 15-19 : there are 5 results
So the longest bar in her histogram is the Intervals 5-9 with the value of 5
Hope it will find you well.