I want you to imagine as you read this or you can draw through the help of my explanation and see yourself:
1↪Draw triangle ABC where BC>AC
2↪D is any point on AC such that CD=CB
3↪Roughly drawing , you can assume CD=CB and and join BD
4↪SO triangle ABC which is a big triangle is divided into Triangles ABD and BDC
5↪See in triangle BDC ,CD=CB so, base angles of isosceles triangle are equal:
<CDB=<CBD = x (assume) which means x is acute angle since CDB and CBD are are in same triangle with same measure and there can't be any two obtuse angle in any traingle. So x must be acute.
6↪Now see in traingle ABD,
<ADB=180-<CDB=180-x=obtuse angle
...check yourself ...just subtract any acute angle from 180 you will get only obtuse angle (ie angle greater than 90)
That means in triangle ABD , one angle ADB is obtuse which means remaining <ABD and < BAD are acute. [PROVED]
❇Main Concept Used Here:
↪In any triangle there can be maximum of one obtuse angle...so remaining two must be acute angle otherwise interior angles sum can't be equal to 180.
Answer:
The probability that an individual has the disease and has a positive test result is:
9.8%.
Step-by-step explanation:
Probability of a true positive result for a test of syphilis = 0.98 or 98%
Probability of a false negative result for a test of syphilis = 0.02 or 2% (100 - 98)
Probability of a true negative result for a test of syphilis = 0.9 or 90%
Probability of a false negative result for a test of syphilis = 0.1 or 10% (100 - 90)
Therefore, the probability that an individual has the disease and has a positive test result = 0.98 * 0.1 = 0.098 = 9.8%
2x + 8 would be the simplified version of this question
3m=2(4+t)
3m= 8+2t
3m-8=2t
(divide everything by 2)
3/2m-4=t
t=3/2m-4
