Question

The sum of two numbers is nine. one number is three more than the other. find the numbers

Answer 1

Let the two numbers be x and y.
x+y= 9
x-3=y
Substitute the two equations together
x+x-3=9
2X=12
X=6.
Y= 6-3=3

Answer 2

The required numbers are 6 and 3

Solution:                                                                                              Assume the required numbers are a and b,

Given that the sum of two numbers is nine that is, $a+b=9\rightarrow(1)$

One number is three more than the other that is, $a=b+3\rightarrow(2)$

On substituting (2) in (1) we get,

$\Rightarrow b+3+b=9\rightarrow 2b+3=9$

On grouping the similar terms we get,

$\Rightarrow 2b=9-3 \rightarrow 2b=6 \rightarrow$

$\Rightarrow b=\frac{6}{2}\rightarrow b=3 \rightarrow (3)$

On substituting (3) in (1) we get,

$a+3=9\rightarrow a=9-3\rightarrow a=6$

Therefore, the number are 6 and 3.