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3 years ago

What is 40/21 as a mixed number

Mathematics

2 answers:

Nikitich [7]3 years ago

5 0

$\dfrac{40}{21}=\dfrac{21+19}{21}=\dfrac{21}{21}+\dfrac{19}{21}=1+\dfrac{19}{21}=\boxed{1\dfrac{19}{21}}$

Sveta_85 [38]3 years ago

4 0

Hello ,

40/21 = 21/21 + 19/21
40/21 = 1 + 19/21
40/21 = 1 $\frac{19}{21}$

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Answer:

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Step-by-step explanation:

We know that the height of the rocket is given by the function:

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$350=-16t^2+200t$

The last is a quadratic equation, which can be put in the form $at^2+bt+c=0$ and solved applying the formula:

$t=\frac{-b+-\sqrt{b^2-4ac} }{2a}$

So, let's put the equation on the form $at^2+bt+c=0$ adding $16t^2$ and subtracting $200t$ to each side of the equation; the result is:

$16t^2-200t+350=0$

So, we note that a=16, b=-200, and c=350.

Then,

$t_1=\frac{200-\sqrt{200^2-4*16*350} }{2*16}=2.10$

$t_2=\frac{200+\sqrt{200^2-4*16*350} }{2*16}=10.40$

According to the equation, that are the times for which the height will be 350 ft; that is because the rocket is going to ascend and then to fail again to the ground.

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