Answer:
(a) 0.2061
(b) 0.2514
(c) 0
Step-by-step explanation:
Let <em>X</em> denote the heights of women in the USA.
It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.
(a)
Compute the probability that the sample mean is greater than 63 inches as follows:

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.
(b)
Compute the probability that a randomly selected woman is taller than 66 inches as follows:

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.
(c)
Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.
Answer:
<QPR = 98.5 degrees
Step-by-step explanation:
a line = 180 degrees
7x + 4 + 9x - 40 = 180
16x - 36 = 180
16x = 216
x = 13.5
<QPR = 7x + 4 = 7(13.5) + 4 = 98.5
It simplifies down to x + 4
Hope I helped C:
I had that problem before on a test i got it wrong :(