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Brums [2.3K]
3 years ago
8

Mia’s cell phone plan: $15 a month plus free texts plus $2.50 per GB of high-speed data. Mia used 3.8 GB and sent 110 texts. How

much does she have to pay?
Mathematics
2 answers:
SashulF [63]3 years ago
7 0
I’m not sure but u multiply 2.5 by 3.8 to get amount she has to pay for GB. Since it free texts so 2.5 • 3.8 = $9.5 plus $15 which give $24.5
I could be wrong..
nirvana33 [79]3 years ago
6 0
2.5*3.8=9.5 +15(flat rate) = 24.5$
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Answer:

(a) 0.2061

(b) 0.2514

(c) 0

Step-by-step explanation:

Let <em>X</em> denote the heights of women in the USA.

It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

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3 years ago
Help please!!!!!!!!!!!!!
fiasKO [112]

Answer:

<QPR = 98.5 degrees

Step-by-step explanation:

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16x - 36 = 180

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