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FromTheMoon [43]
3 years ago
11

Petra jogs 3 miles in 30 minutes. At this rate, how long would it take her to jog 7 miles?

Mathematics
1 answer:
NikAS [45]3 years ago
8 0
30 minutes / 3 miles = 10 minutes for 1 mile

7 miles * 10 minutes per mile = 70 minutes total to run 7 miles
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Ryan won 60 tickets playing a game at the arcade. He gave four tickets
3241004551 [841]

Answer:

60 tickets he gave 13 friends 4 tickets

13 friends

Step-by-step explanation:

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3 years ago
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The table shows the year groups of some students who use the canteen. Mr Ford wants to survey 50 of these students stratified by
igor_vitrenko [27]

7 more year 9 students than year 8 students should be surveyed, If Mr.Ford wants to survey 50 of these students stratified by year group.

Step-by-step explanation:

The given is,

                    Year                        Students

                       7                                 80

                       8                                 110

                       9                                 160

                    Total                              350

           Mr.Ford wants to survey 50 of these students stratified by year group.

Step:1

           Formula to find the ratio of number of grouped students to total students,

                           Ratio, r = \frac{Number of students grouped }{Total number of students}

                                         = \frac{50}{350}

                                         = 0.1428

Step:2

          Formula for Number of students surveyed from year wise,

          For year 7 students,

                                         = (Ratio) × (Students from year 7)

                                         = 0.1428 × 80

                                         = 11.424

                                        ≅ 11               (∵ For students we convert into whole number)

         For year 8 students,

                                         = (Ratio) × (Students from year 8 )

                                         = 0.1428 × 110

                                         = 15.708

                                        ≅ 16               (∵ For students we convert into whole number)

          For year 8 students,

                                         = (Ratio) × (Students from year 9 )

                                         = 0.1428 × 160

                                         = 22.8

                                        ≅ 23             (∵ For students we convert into whole number)

Step:3

          To find How many more year 9 students than year 8 students should be in the survey

                                        = ( Students from year 8 for group) -

                                                                     ( Students from year 8 for group)

                                        = 23 - 16

                                        = 7 students

Result:

          7 more year 9 students than year 8 students should be surveyed, If Mr.Ford wants to survey 50 of these students stratified by year group.

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3 years ago
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(x + 1)(x - 1)<br> I dont understand this could any1 help me
mr_godi [17]

Answer:

x^2-1

Step-by-step explanation:

you must use the distributive property

first you do x•x=x^2,

then you do x•1 and x•-1 to get x and -x and those cancel out,

the you do 1•-1=-1, then you put it together to get x^2-1

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2 years ago
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According to records, the amount of precipitation in a certain city on a November day has a mean of inches, with a standard devi
Mekhanik [1.2K]

Answer:

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}, in which \mu is mean amount of inches of rain and \sigma is the standard deviation.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Mean \mu, standard deviation \sigma

n days:

This means that s = \frac{\sigma}{\sqrt{n}}

Applying the Central Limit Theorem to the z-score formula.

Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

What is the probability that the mean daily precipitation will be of X inches or less for a random sample of November days?

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}, in which \mu is mean amount of inches of rain and \sigma is the standard deviation.

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3 years ago
Company x has 128000 in a savings account that pays 6% interest per year. How much interest will it earn at the end of the year?
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Step-by-step explanation:

234'00

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