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Marizza181 [45]
3 years ago
5

Write the decimal as a percent. 0.0371 = %

Mathematics
2 answers:
musickatia [10]3 years ago
6 0
Answer is - 3.79%
0.0371 = 3.17/100
NARA [144]3 years ago
6 0
3.79% would be the percentage
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If a rink is 3 times its width and the width is 10m what is the area
emmainna [20.7K]
300m because area is Length x width and it's 3x as big as 10 meters it's 30 x 10= 300
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4 years ago
The function f(x) is shown in this graph please help because I can’t understand this concept
Pavlova-9 [17]

Answer:

d) the slope of f(x) is greater than the slope of g(x)

Step-by-step explanation:

to find the slope of an equation, you look at its rise/run. for f(x), you can see that from one point (0, 3) to another (1, 1) it goes down 2 values (3 - 1) and over 1 value (0 + 1). because it goes down 2 values, the rise is -2, and because it moves to the side 1 value positively, the run is +1.

-2/+1 = -2. this means the slope of f(x) = -2.

finally, it says the slope of g(x) = -6, and -2 > -6. i hope this helps! :)

4 0
3 years ago
Solve for h.<br><br> 2 &lt; -19 - 7h
Sunny_sXe [5.5K]

Answer:

h < -3

Step-by-step explanation:

2 < -19 -7h

or 19 + 2 < -7h

or 21 < -7h

or 21/(-7) > h [flip the sign when dividing with negative Number ]

∴ -3 > h ( h < -3 )

hoping that this will help you

Please Mark as Brainliest...

5 0
2 years ago
Read 2 more answers
Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (
Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

P(\frac{T}{S}) = 0.95

P(\frac{T}{S^c}) = 0.05

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

P(S^c) =  1 - P(S)

= 1 - 0.3

= 0.7

ii. P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}

= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }

= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}

= 0.8906

iii. P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}

= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }

= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}

= 0.0221

We simply applied the above formulas so that the each part could come

8 0
3 years ago
The equation $y = -6t^2 - 10t + 56$ describes the height (in feet) of a ball thrown downward at 10 feet per second from a height
blondinia [14]

Answer:

2.33 Seconds

Step-by-step explanation:

The equation y = -6t^2 - 10t + 56 expresses the height of a ball at a given time, t, on the planet Mars.  We are also given that the ball is thrown with a velocity of 10 feet per second with the initial height of 56 feet.

To find the amount of time to reach the ground, we can say that the time being found will be when the ball is on the ground, or when y = 0.  So we simply set our equation to 0 and solve for t.

y = -6t^2 - 10t + 56

0 = -6t^2 - 10t + 56

0 = -1 (6t^2 + 10t + -56)

0 = -1 (3t - 7) (2t + 8)

(3t - 7) = 0  OR (2t + 8) = 0

3t = 7         OR  2t = -8

t = 7/3        OR    t = -4

Since time will not be negative, we will want to choose the positive solution for this quadratic equation.

Hence, the amount of time for the ball to hit the ground will be 7/3 seconds or 2.33 seconds.

Cheers.

5 0
3 years ago
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