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Olenka [21]
4 years ago
9

If this trend​ continues, in which year will 73% of babies be born out of​ wedlock?

Mathematics
1 answer:
antoniya [11.8K]4 years ago
7 0
Sometime in the year of 2156
hope this helps 0-0
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I need help showing my work for 67.42 \4
pychu [463]
If the image does not open, just let me know 

7 0
3 years ago
A bookstore had 90 copies of a magazine. Yesterday, it sold 1/6 of them. Today, it sold 1/5 of what remained. How many copies do
MA_775_DIABLO [31]

Answer:

60 copies

Step-by-step explanation:

first you take 1/6th of the original 90 copies which is 15 and subtract that from the 90, you are left with 75 copies which is how many they had left at the end of yesterday. then you take 1/5th of the 75 copies that are left which is also 15 and you subtract that from 75 and you get 60. that's why at the end of today there are 60 copies left.

6 0
4 years ago
An item is regularly priced at $31. It is now priced at a discount of 55% off the regular price.
Alekssandra [29.7K]
17.05 I think..
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5 0
3 years ago
Assume that the Poisson distribution applies and that the mean number of hurricanes in a certain area is 6.9 per year. a. Find t
VLD [36.1K]

Answer:

a) 9.52% probability​ that, in a​ year, there will be 4 hurricanes.

b) 4.284 years are expected to have 4 ​hurricanes.

c) The value of 4 is very close to the expected value of 4.284, so the Poisson distribution works well here.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

6.9 per year.

This means that \mu = 6.9

a. Find the probability​ that, in a​ year, there will be 4 hurricanes.

This is P(X = 4).

So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 4) = \frac{e^{-6.9}*(6.9)^{4}}{(4)!}

P(X = 4) = 0.0952

9.52% probability​ that, in a​ year, there will be 4 hurricanes.

b. In a 45​-year ​period, how many years are expected to have 4 ​hurricanes?

For each year, the probability is 0.0952.

Multiplying by 45

45*0.0952 = 4.284.

4.284 years are expected to have 4 ​hurricanes.

c. How does the result from part​ (b) compare to a recent period of 45 years in which 4 years had 4 ​hurricanes? Does the Poisson distribution work well​ here?

The value of 4 is very close to the expected value of 4.284, so the Poisson distribution works well here.

5 0
3 years ago
-12=-8z+12 please need help​
miss Akunina [59]

Answer:

z=3

Step-by-step explanation:

-12=-8z+12

-12-12=-8z

-24=-8z

-24/-8=z

z=24/8

3=z

z=3

8 0
3 years ago
Read 2 more answers
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