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vodomira [7]
3 years ago
10

Solve the following equations:2x-5y-4 x+6y=15​

Mathematics
1 answer:
Sauron [17]3 years ago
8 0

Answer:

x= 3

y= 2

Step-by-step explanation:

The given equations are :

2x-5y = -4    equation 1

x +6y = 15    equation 2

We will multiply the equation:2 by 2

2(x+6y=15)

2x+12y=30   equation 3

Lets call this equation:3

Now we will use the elimination method:

Subtract equation 3 from equation 1:

2x-5y = -4

2x+12y=30

_________

   -17y = -34

y= -34/-17

y = 2

Now put the value of y in any equation:

We will use equation 1

2x-5y = -4

2x-5(2)= -4

2x-10= -4

Move the constant to the R.H.S

2x= -4+10

2x=6

Divide both the terms by 2

x= 3

Therefore the solution set is (x,y){(3,2)}....

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klasskru [66]

Answer:

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Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Sari is factoring the polynomial 2x2 + 5x + 3. What is the missing number in her factorization?
-BARSIC- [3]
2x2 + 5x + 3

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8 0
3 years ago
Sole for |p+8| over 2 =5
Lubov Fominskaja [6]

Answer:

p =2                     p=-18

Step-by-step explanation:

|p+8|

-------------- = 5

2

Multiply each side by 2

|p+8|

-------------*2 = 5*2

2

|p+8|  =10

There is a positive and a negative solution

p+8=10         p+8=-10

Subtract 8 from each side

p+8-8=10-8         p+8-8=-10-8

p =2                     p=-18



7 0
3 years ago
The graphs below have the same shape. What is the equation of the blue graph? ​
muminat
I am not that really sure but ig its 5
6 0
2 years ago
G 3.6 Dice rolls. If you roll a pair of fair dice, what is the probability of (a) getting a sum of 1
Paladinen [302]

Answer:

0

Step-by-step explanation:

In the roll of a pair of fair dice, The sample space is as follows:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

If x,y represent  the  possible outcome of rolling the two die

Then the total number of possibilities for  the sample space = (x,y)

= (6 × 6) = 36

Now, the probability of getting a sum of 1 does not exist in the roll of a pair of  fair dice.

Therefore, Probability(1) = 0

8 0
3 years ago
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