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zmey [24]
3 years ago
10

Find factors of 14y^2+41y+15

Mathematics
1 answer:
baherus [9]3 years ago
4 0
<span>(7y + 3) • (2y + 5) im not sure it's that answer ☺
</span>
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Solve for x<br> 3/10 = x/7<br> Give your answer as an improper fraction in its simplest form!!!!!
julsineya [31]

Answer:

x = 21/10

Step-by-step explanation:

3/10 = x/7

Cross multiply.

10x = 21

x = 21/10

5 0
3 years ago
Read 2 more answers
How 7/3 compares to 2 1/3
alekssr [168]
7/3 written as a mixed fraction is 2 1/3

So 

7/3 = 2 1/3

3 0
3 years ago
What does 5/7c=13/14 equal
natita [175]
To find c, you must isolate it.
To do this, you must divide both sides by 5/7, since that is being multiplied by c and you must do the inverse to it to cancel it out in order to leave c by itself.

5/7c ÷ 5/7 = c

13/14 ÷ 5/7
To divide fractions, follow these steps:
Step 1- Turn the second fraction, 5/7 in this case, into its reciprocal. This means swapping the places of the numerator and denominator.
5/7 reciprocal = 7/5

Step 2- multiply the original first fraction and reciprocal second fraction.
13/14 • 7/5
13 • 7 = 91
14 • 5 = 70
13/14 ÷ 5/7 = 91/70

Step 3- Simplify if possible.
91/70
Since 70 can go into 90, you can turn this into a mixed number.
1 and 21/70
Now simplify 21/70.
Both can be divided by 7.
21 ÷ 7 = 3
70 ÷ 7 = 10
So simplified, 91/70 equals 1 and 3/10.
As a decimal, this is 1.3.

So the answer is c = 1.3, or 1 and 3/10.

Hope this helps :)
8 0
4 years ago
Exponents of Zero<br> Simplify x^0, where <br> x does not equal 0
densk [106]

Answer:

  1

Step-by-step explanation:

Any non-zero value raised to the zero power is 1.

  x^0 = 1

7 0
4 years ago
The projectile motion of an object can be modeled using s(t) = gt2 + v0t + s0, where g is the acceleration due to gravity, t is
Tom [10]

Answer: 0=-4.9t²+19.6t+24.5

Step-by-step explanation:

s(t)=gt^2+v_0t+s_0\\v_0=19,6\ \frac{m}{s} \ \ \ \ s_0=24,5\ m\ \ \ \ g=-4,9\ \frac{m}{s^2} \ \ \ \ S(t)=0\ (the\  object  \ hitts\  the \ ground)\  \Rightarrow\\0=-4,9t^2+19,6t+24,5.

4 0
2 years ago
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