Answer:
-3/8= -6/16=-9/24=-12/32=-15/40....
3/8=6/16=9/24=12/32=15/40=18/48=21/56.....
Answer:
51.96 mm² approximately
Step-by-step explanation:
the first thing you should know is that the area of a rectangle is base*height sin of (
the included angle i.e
Arectangle= bh sin90° since all angles of a rectangle are equal then the included angle is 90°
<em>Arectangle= bh sin90° since sin90 is 1 we simply use the equation bh because multiplying bh by one is bh. bearing this in mind , the area of the parallelogram can be calculated as:</em>
Aparallelogram= bh sin of sin of the included angle
Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°
Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°Aparallelogram=60mm² * 0.866
Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°Aparallelogram=60mm² * 0.866Aparallelogram=51.96 mm² approximately
Answer:
[22 x 21] / 2=231 or "c"
Step-by-step explanation:
Please consider the attached image for complete question.
We have been given that measure of arc WY is 76° and and measure of arc XZ is 112°. We are asked to find the difference of of the measures of angle WPY and angle XPY.
First of all we will find the measure of angle WPY using intersecting secants theorem. Intersecting secants theorem states that measure of angle formed by two intersecting secants inside a circle is half the sum of intercepting arcs.
We can see that angle WPY and angle XPY are linear angles, so they will add up-to 180 degrees.
Now we need to find difference of both angles as:
Therefore, the difference of the measures of angle WPY and angle XPY is 8 degrees.
Answer:
200
Step-by-step explanation:
