The surface area of the prism is equal to the summed up area of the faces of the triangular prism.
The bases of the prism would be triangles with an unknown base, b, and height of 3. The area of the base is calculated through the equation,
A = bh/2
where b is base and h is height. Substituting the values,
A = b(3)/2
Since there are two bases, the contribution of the triangles for the surface area is,
2A = 3b
Next we calculate for the area of the triangle sides with length equal to b (same as the base of the triangle).
Area = b(12 km)
There are 3 sides such that the total area becomes,
Area = 36b
Hence, the surface area is,
48.735 km² = 3b + (36b)
The value of b from the equation is 1.25 km
<em>ANSWER: 1.25 km</em>
Answer:
x1=8
x2=1/5
Step-by-step explanation:
<u>ANSWER</u>
<u>EXPLANATION</u>
This very simple to do.
First locate the entry in 
in matrix A. That is the entry in the intersection of the fourth row and first column of matrix A. This entry is 
.
Then multiply by the scalar which is 2 to get,
.
Next we locate the entry in 
in matrix B also. Which is 
. We multiply by the scalar of 
to get,
.
We now add these two corresponding entries to obtain,
See diagram
