<span>Square root of y^2 = y
so
</span><span>Square root of y^2 times y^2 = y * y^2 = y^3
answer
y^3</span>
Answer:
y = –7x – 11
6x – 4y = 10
Step-by-step explanation:
From the question given above, we obtained:
x = –1
y = –4
y = ?x – 11 ....... (1)
6x – ?y = 10b......... (2)
Let the two unknown be a and b. Thus the above equation becomes:
y = ax – 11 ......... (3)
6x – by = 10 .......(4)
Next, we shall determine the value of 'a' and 'b'. This can be obtained as follow:
For a:
y = ax – 11
x = –1
y = –4
–4 = a(–1) – 11
–4 = –a – 11
Collect like terms
–4 + 11 = –a
7 = –a
Multiply through by –1
a = –7
For b:
6x – by = 10
x = –1
y = –4
6(–1) – b(–4) = 10
–6 + 4b = 10
Collect like terms
4b = 10 + 6
4b = 16
Divide both side by 4
b = 16 / 4
b = 4
Finally, we shall substitute the value of a and be into equation 3 and 4 respectively.
y = ax – 11
a = –7
y = –7x – 11
6x – by = 10
b = 4
6x – 4y = 10
Therefore, the complete equation are:
y = –7x – 11
6x – 4y = 10
What are you trying to find?
Answer:
Since 
and 
, then the quadrilateral ABCD is a parallelogram.
Step-by-step explanation:
First, we label each point of the quadrilateral with the help of a graphing tool. If the quadrilateral ABCD is a parallelogram, then and . If we know that 
, 
, 
and 
, then the measure of each vector is, respectively:
Since and , then the quadrilateral ABCD is a parallelogram.
