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anygoal [31]
3 years ago
15

Find the approximate side length of a square game board with an area of 194 in2.

Mathematics
1 answer:
Mazyrski [523]3 years ago
7 0

Answer:

root 194=13.928 inches

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Write 10 feet and 4 yards as a fraction in simplest form
S_A_V [24]
⅚. You first find out how many feet are in a yard (three). Then you write the fraction- 10/12. Then you reduce. The number two can evenly go into both of those numbers. Ten divided by two is five. Twelve divided by two is six. So, your final answer is ⅚.
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3 9/12 + (4 7/12 + 5/12) = 3 9/12 + ____?
Maru [420]

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5

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*<br> Find the area of a triangle: Base of 8 cm Hight of 9 cm
Sliva [168]

Answer:

36 cm

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1.2 The following pattern is given: -100,-97; -91;
elena55 [62]

Brainly 505 Server Error

7 0
2 years ago
Please someone help me to prove this. ​
morpeh [17]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ

Use the Sum/Difference Identities:

sin(α + β) = sinα · cosβ + cosα · sinβ

cos(α - β) = cosα · cosβ + sinα · sinβ

Use the Unit circle to evaluate: sin45 = cos45 = √2/2

Use the Double Angle Identities:   sin2Ф = 2sinФ · cosФ

Use the Pythagorean Identity: cos²Ф + sin²Ф = 1

<u />

<u>Proof LHS → RHS</u>

LHS:                                  2sin(45 + 2A) · cos(45 - 2A)

Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)

Unit Circle:    2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]  

Expand:        2[(1/2)cos²2A  + cos2A·sin2A + (1/2)sin²2A]

Distribute:              cos²2A   + 2cos2A·sin2A + sin²2A  

Pythagorean Identity:    1 + 2cos2A·sin2A

Double Angle:                1 + sin4A

LHS = RHS:  1 + sin4A = 1 + sin4A   \checkmark

6 0
3 years ago
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