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Korolek [52]
3 years ago
8

What is 4√32+6√50 in simplified radical form

Mathematics
2 answers:
myrzilka [38]3 years ago
3 0

Simplify the following:
4 sqrt(32) + 6 sqrt(50)
sqrt(32) = sqrt(2^5) = 2^2 sqrt(2):
4×2^2 sqrt(2) + 6 sqrt(50)
2^2 = 4:
4×4 sqrt(2) + 6 sqrt(50)
sqrt(50) = sqrt(2×5^2) = 5 sqrt(2):
4×4 sqrt(2) + 6×5 sqrt(2)
4×4 = 16:
16 sqrt(2) + 6×5 sqrt(2)
6×5 = 30:
16 sqrt(2) + 30 sqrt(2)
16 sqrt(2) + 30 sqrt(2) = 46 sqrt(2):
Answer: 46 sqrt(2)
Klio2033 [76]3 years ago
3 0
24 -/160 simplify it i can't simplify it
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Suppose there is a 13.9 % probability that a randomly selected person aged 40 years or older is a jogger. In​ addition, there is
Blababa [14]

Answer:

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.

It would be unusual to randomly select a person aged 40 years or older who is male and jogs.

Step-by-step explanation:

We have these following probabilities.

A 13.9% probability that a randomly selected person aged 40 years or older is a jogger, so P(A) = 0.13.

In​ addition, there is a 15.6% probability that a randomly selected person aged 40 years or older is male comma given that he or she jogs. I am going to say that P(B) is the probability that is a male. P(B/A) is the probability that the person is a male, given that he/she jogs. So P(B/A) = 0.156

The Bayes theorem states that:

P(B/A) = \frac{P(A \cap B)}{P(A)}

In which P(A \cap B) is the probability that the person does both thigs, so, in this problem, the probability that a randomly selected person aged 40 years or older is male and jogs.

So

P(A \cap B) = P(A).P(B/A) = 0.156*0.139 = 0.217

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.

A probability is unusual when it is smaller than 5%.

So it would be unusual to randomly select a person aged 40 years or older who is male and jogs.

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Step-by-step explanation:

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