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barxatty [35]
3 years ago
8

Which function has a range of y < 3? y=3(2)x y=2(3)x y=-(2)x +3 y = (2)x - 3

Mathematics
2 answers:
katovenus [111]3 years ago
6 0

Answer:

Step-by-step explanation:

Dmitriy789 [7]3 years ago
3 0

Answer:

\large\boxed{y=-(2)^x+3}

Step-by-step explanation:

\text{A function y = a(b)}^x\ \text{has a range:}\\\\y0\\\\f(x)+n-\text{shift a graph}\ n\ \text{units up}\\f(x)-n-\text{shift a graph}\ n\ \text{units down}\\f(x+n)-\text{shift a graph}\ n\ \text{units to the left}\\f(x-n)-\text{shift a graph}\ n\ \text{units to the right}\\\\\text{We have the range}\ y

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Help me please!!!!!!!
Dimas [21]

Answer:

Will you do somemthing for me

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A survey is conducted to find out whether people in metropolitan areas obtain their news from television (Event T), an newspaper
MrMuchimi

Answer:

e) P ( R' | T ) = 0.62857

f)  P ( T' | N ) = 0.32258

g)  P ( R' | N ) = 0.70968

h) P ( T' | N&R ) = 5/6

Step-by-step explanation:

Given:

- The probability of Television as news source P ( T ) = 0.7

- The probability of Newspaper as news source P ( N ) = 0.62

- The probability of Radio as news source P ( R ) = 0.46

- The probability of Television & Newspaper as news source P (T&N) = 0.42

- The probability of Television & Radio as news source P (T&R) = 0.26

- The probability of Radio & Newspaper as news source P (R&N) = 0.18

- The probability of all 3 as news source P ( T & R & N ) = 0.03

Find:

Given that TV is a news source, what is the probability that radio is not a news source?

Given that newspaper is a news source, what is the probability that TV is not a news source?

Given that newspaper is a news source, what is the probability that radio is not a news source?

Given that both newspaper and radio are news sources, what is the probability that TV is not a news source?

Solution:

- We will first compute the individual probability of each event occurring alone.

   P (Television is the only news source) = P(T) - P(T&R) - P(T&N) + P(T&N&R)

   P ( Only Television ) = P ( only T ) = 0.7 - 0.42 - 0.26 + 0.03 = 0.05

   P (Newspaper is the only news source) = P(N)-P(N&R)-P(T&N)+P(T&N&R)

   P ( Only Newspaper ) = P ( only N ) = 0.62 - 0.18 - 0.42 + 0.03 = 0.05

   P (Radio is the only news source) = P(R) - P(T&R) - P(N&R) + P(T&N&R)

   P ( Only Radio ) = P ( only R ) = 0.46 - 0.26 - 0.18 + 0.03 = 0.05

- Now for part e)

   We are asked for a conditional probability of the form as follows:

            P ( R' | T ) = P ( R' & T ) / P ( T )

   First compute the probability that next news source is not Radio provided it is already a source of TV.                              

            P ( R' & T ) =  P( only T ) + P ( only T & N ) = 0.05 + 0.42 - 0.03 = 0.44

Hence,

            P ( R' | T ) = 0.44 / 0.7

            P ( R' | T ) = 0.62857

- Now for part f)

   We are asked for a conditional probability of the form as follows:

            P ( T' | N ) = P ( T' & N ) / P ( N )

   First compute the probability that next news source is not TV provided it is already a source of Newspaper.                              

            P ( T' & N ) =  P( only N ) + P ( only R & N ) = 0.05 + 0.18 - 0.03 = 0.2

Hence,

           P ( T' | N ) = 0.2 / 0.62

           P ( T' | N ) = 0.32258

- Now for part g)

   We are asked for a conditional probability of the form as follows:

            P ( R' | N ) = P ( R' & N ) / P ( N )

   First compute the probability that next news source is not Radio provided it is already a source of Newspaper.                              

            P ( R' & N ) =  P( only N ) + P ( only T & N ) = 0.05 + 0.42 - 0.03 = 0.44

Hence,

            P ( R' | N ) = 0.44 / 0.62

            P ( R' | N ) = 0.70968

- Now for part h)

   We are asked for a conditional probability of the form as follows:

            P ( T' | N&R ) = P ( T' & N & R) / P ( N & R )

   First compute the probability that next news source is not TV provided it is already a source of both radio and Newspaper.                              

            P ( T' & N & R) = P ( only N & R ) = 0.18 - 0.03 = 0.15

Hence,

            P ( T' | N&R ) = 0.15 / 0.18

            P ( T' | N&R ) = 5/6

6 0
3 years ago
Find the coordinates of the missing vertex of rectangle ABCD with A(−5, 4), B(2, 4), and C(2, 0).
svlad2 [7]

Answer:

Answer:

safe speed for the larger radius track u= √2 v

Explanation:

The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.

Also given that r_1= smaller radius

r_2= larger radius curve

r_2= 2r_1..............i

let u be the speed of larger radius curve

now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=

r

1

mv

2

=

r

2

mu

2

................ii

form i and ii we can write

v^2= \frac{1}{2} u^2v

2

=

2

1

u

2

⇒u= √2 v

therefore, safe speed for the larger radius track u= √2 v

6 0
3 years ago
Half of sarans wire is equal to 2/5 of daniel's. chris has 3 times as much as sarah. in all, their wire is 6 feet. how long is s
Pepsi [2]
You need to make a series of equations from what you are given first. I am going to use the first letter of each of the names to represent the length of that persons wire.
1/2s=2/5d
3c=s
s+d+c=6 ft

Okay. Now you can combine the first two equations knowing what s equals:
1/2(3c)=2/5d
d=15c/4

Now you have d=15c/4 and s=3c, so you can replace d and s in the third equation.

3c+15c/4+c=6

Then solve for c and plug it into the equation 3c=s to find the length of sarah's wire.
7 0
3 years ago
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nikitadnepr [17]
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7 0
3 years ago
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