So I'm hoping you mean 6, or else the probability is 0. So the possible ways of getting a sum of 6 is 1&5, 2&4, 3&3, 4&2, 5&1. There are 36 different ways of rolling the dice, so divide the 5 possible ways by 36. Then, we need to add the possibility of getting at least one 6 in the roll. It doesn't matter what the other die is, so for each die, the probability is 1/6, and for both, the probability is 2/6. Add this to the probability of getting a sum of 6, and you get your answer.
This is a quotient (division) of two functions we must be concerned with the fact that division by zero is undefined.
Since g(x) is in the divisor position, it cannot equal 0.
Subtract 6 from both sides to solve.
So the domain is all real numbers except -6
Set notation {x | x ∈ R, x ≠ -6}
Interval notation (-∞,-6)∪(-6,∞)
Answer:
<em>C</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em> </em><em>answer</em><em> </em><em>of</em><em> </em><em>464657474+64736825483</em><em> </em><em>is</em><em> </em><em>65201482957</em>
Answer:
Step-by-step explanation:
Pythagoras theorem
a^2=b^2+c^2
(x-2)^2=9^2+(x+1)^2
x^2-4x+4=81+x^2+2x+1
Collect like terms
-4x-2x=82-4
-6x=78
x=-13
