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3 years ago

Please help me ASAP I’ll mark Brainly

Mathematics

1 answer:

gregori [183]3 years ago

4 0

Answer:

Step-by-step explanation:

Prove

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How do I find the quotient 7/8÷2/9

Lena [83]

$\dfrac{\frac{7}{8}}{\frac{2}{9}}=\frac{7}{8}\cdot\frac{9}{2}=\frac{63}{16}$

5 0

3 years ago

Read 2 more answers

Y=-4x y=x^2-12 solve the system of equations

anygoal [31]

Answer:(-6,24) and (2,c8)

Step-by-step explanation:

7 0

3 years ago

HELPP!!

s344n2d4d5 [400]

Answer:

2 km

Step-by-step explanation:

basically do the inverse:

3×4(instead of divide)=12

12-8=4

it says jose ran 2× as many km as karen so you divide 4 by 2 giving you 2

sorry if its incorrect

6 0

2 years ago

The sum of 3 consecutive integers is 47 more than the first integer. Find the three integers.

ss7ja [257]

Answer:

22,23,24

Step-by-step explanation:

Well, you need to first find two consecutive integers that add up to 47, because that is the difference between the first digit and the total. This happens to be 23 and 24. Once you get these two numbers, the 22 comes intuitively, as you have to add 23 and 24 to get a difference between 22 and (22+23+24).

7 0

3 years ago

The probability that a lab specimen contains high levels of contamination is 0.10. A group of 4 independent samples are checked.

galben [10]

Answer:

a) 0.6561

b) 0.2916

c) 0.3439

Step-by-step explanation:

We are given the following information:

Let us treat high level of contamination as our success.

p = P(High level of contamination) = P(success) = 0.10

n = 4

The, by binomial distribution:

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}\\\text{where x is the number of success}$

a) P(No high level of contamination)

We put x = 0, in the formula.

$P(X=0) = \binom{4}{0}.(0.10)^0.(1-0.10)^{4} =0.6561$

Probability that no lab specimen contain high level of contamination is 0.6561

b) P(Exactly one high level of contamination)

We put x = 1, in the formula.

$P(X=1) = \binom{4}{1}.(0.10)^1.(1-0.10)^{3} =0.2916$

Probability that no lab specimen contain high level of contamination is 0.6561

c) P(At least one contains high level of contamination)

$p(x \geq 1) = 1 - p( x = 0) = 1 - 0.6561 = 0.3439$

Probability that at least 1 lab specimen contain high level of contamination is 0.3439

8 0

3 years ago