-3(4v+1)-3(2v+3) how do you simplify

Mathematics

2 answers:

PolarNik [594]3 years ago

7 0

$-3(4v+1)-3(2v+3) =\\
-12v-3-6v-9=\\
-18v-12$

Shtirlitz [24]3 years ago

4 0

First you have to multiply the numbers out of the paranthesis, with the numbers in it:
$-3(4v+1)-3(2v+3)\\ -3\cdot 4v-3\cdot 1-3\cdot 2v-3\cdot 3$
then solve :
$-12v-3-6v-9\\ -18v-12$

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A market research firm supplies manufacturers with estimates of the retail sales of their products from samples of retail stores

KengaRu [80]

Answer:

The 95% confidence interval for the difference of means is (7.67, 16.33).

The estimate is Md = 12.

The standard error is sM_d = 2.176.

Step-by-step explanation:

We have to calculate a 95% confidence interval for the difference between means.

The sample 1 (this year's sales), of size n1=36 has a mean of 53 and a standard deviation of 12.

The sample 2 (last year's sales), of size n2=49 has a mean of 41 and a standard deviation of 6.

The difference between sample means is Md=12.

$M_d=M_1-M_2=53-41=12$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{12^2}{36}+\dfrac{6^2}{49}}\\\\\\s_{M_d}=\sqrt{4+0.735}=\sqrt{4.735}=2.176$