2.6×3 1/3<br> round answer to 3 decimal places

HELP MEE AND PLEASE HURRY

chubhunter [2.5K]

Answer:

maybe always true because that is number

4 0

3 years ago

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Two different types of polishing solutions are being evaluated for possible use in a tumble-polish operation for manufacturing i

Nina [5.8K]

Answer:

$z=\frac{0.843-0.653}{\sqrt{0.748(1-0.748)(\frac{1}{300}+\frac{1}{300})}}=5.358$

$p_v =2*P(Z>5.358) = 4.2x10^{-8}$

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that we have singificantly differences between the two proportions.

Step-by-step explanation:

Data given and notation

$X_{1}=253$ represent the number with no defects in sample 1

$X_{2}=196$ represent the number with no defects in sample 1

$n_{1}=300$ sample 1

$n_{2}=300$ sample 2

$p_{1}=\frac{253}{300}=0.843$ represent the proportion of number with no defects in sample 1

$p_{2}=\frac{196}{300}=0.653$ represent the proportion of number with no defects in sample 2

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

$\alpha=0.05$ significance level given

Concepts and formulas to use

We need to conduct a hypothesis in order to check if is there is a difference in the the two proportions, the system of hypothesis would be:

Null hypothesis: $p_{1} - p_2}=0$

Alternative hypothesis: $p_{1} - p_{2} \neq 0$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{253+196}{300+300}=0.748$

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.843-0.653}{\sqrt{0.748(1-0.748)(\frac{1}{300}+\frac{1}{300})}}=5.358$

Statistical decision

Since is a two sided test the p value would be:

$p_v =2*P(Z>5.358) = 4.2x10^{-8}$

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that we have singificantly differences between the two proportions.

5 0

4 years ago

What is the concept of rounding decimals? Please be certain to leave an example

a_sh-v [17]

Look at the digit to the right of the required number. If it is a 5 or greater, add 1 to previous digit.
If it is less than 5, leave the previous digit unchanged. In either case, drop all the remaining digits. Example: Round off this decimal 7.253896 to three decimal digits.
Answer. 7.253896approximately7.254
(The wavy equal sign approximately means "is approximately equal to.")
To round off to three decimal digits, we must look at the digit in the fourth place. The digit in the fourth place is 8 (greater than 5). Therefore, we add 1 to the previous digit 3.

8 0

3 years ago

I need help with this question to

madam [21]

Well if you have a question, why dont you post the question....

7 0

4 years ago

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An opinion poll asks a simple random sample of 100 college seniors how they view their job prospects. In all, 53 say "good." Doe

ValentinkaMS [17]

Answer:

We are tryng to proof if more than half of all seniors think their job prospects are good so that would be the alternative hypothesis and the complement rule would be the null hypothesis.:

Null hypothesis: $p\leq 0.5$

Alternative hypothesis: $p > 0.5$

Step-by-step explanation:

Information provided

n=100 represent the random sample ofcollege senior selected

X=53 represent the college seniors who say good

$\hat p=\frac{53}{100}=0.53$ estimated proportion of seniors who think their job prospects are good

$p_o=0.5$ is the value that we want to test

z would represent the statistic

$p_v$ represent the p value

System of hypothesis

We are tryng to proof if more than half of all seniors think their job prospects are good so that would be the alternative hypothesis and the complement rule would be the null hypothesis.:

Null hypothesis: $p\leq 0.5$

Alternative hypothesis: $p > 0.5$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we have:

$z=\frac{0.53 -0.5}{\sqrt{\frac{0.5(1-0.5)}{100}}}=0.6$

The p value for this case would be given by

$p_v =P(z>0.6)=0.274$

7 0

4 years ago

2.6×3 1/3 round answer to 3 decimal places