Given:
Sum of three consecutive integers is more than 62.
To find:
The inequality to represent the above situation then solve your inequality.
Solution:
Let the three consecutive integers are
respectively.
Sum of three consecutive integers is more than 62. So,
![x+(x+1)+(x+2)>62](https://tex.z-dn.net/?f=x%2B%28x%2B1%29%2B%28x%2B2%29%3E62)
![3x+3>62](https://tex.z-dn.net/?f=3x%2B3%3E62)
Subtract 3 from both sides.
![3x>62-3](https://tex.z-dn.net/?f=3x%3E62-3)
![3x>59](https://tex.z-dn.net/?f=3x%3E59)
Divide both sides by 3.
![x>\dfrac{59}{3}](https://tex.z-dn.net/?f=x%3E%5Cdfrac%7B59%7D%7B3%7D)
Therefore, the required inequality is
and solution is
.
Answer:
7
Step-by-step explanation:
Because 7² is 49
∴√49=7
Both formulas equal to y, so they are equivalent to one another.
3x-5 = -3x+4
+5. +5
3x = -3x+9
+3x. +3x
6x = 9
/6. /6
x = 1.5
3(1.5)-5 = y
4.5-5
y = -0.5
J - Jose`s savings;
162 = 9 · j
j = 162 : 9
j = 18
Answer:
Equation is 9 · j = 162 and his savings is 18.