Someone help please! Thank you^ explain the steps to get to the answer also. giving brainliest btw

1. You are designing a rectangular playground. On your scale drawing, the vertices of the rectangle are (6, 3), (6, 5), and (8,

kramer

(8,5) because (6,5) is distance 2 from (6,3). So (8,5) will distance 2 from (8,3)

5 0

2 years ago

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I will give you Brainliest and 500 points if you do this please

aleksley [76]

Answer:

1. C

2. D

Step-by-step explanation:

1.

Pattern A is adding by 2's (1 -> 3, 4 -> 6, 7 -> 9 and so on).

Pattern B is multiplying by 2's (2 -> 4, 3 -> 6, 4 -> 8 and so on).

2.

If 0.25 gallons of paint = 24 ft^2, then 1 gallon will equal?

Set up an equation:

Variable x = area of ft^2 for 1 gallon of paint

0.25/24 = 1/x

Cross multiply

0.25 × x = 24 × 1

0.25x = 24

To make calculations easier, you can convert the decimal into a fraction: 0.25 = 1/4

1/4x = 24

Multiply both sides by 4

1x = 96

x = 96 ft^2

Check your work:

0.25/24 = 1/96

0.25 × 96 = 24 × 1

24 = 24

Correct

6 0

2 years ago

Which of the following number sentences show the correct method to find 43% of 59 Select TWO that apply.

Helen [10]

Answer:

a and b

Step-by-step explanation:

6 0

2 years ago

Costs are rising for all kinds of medical care. The mean monthly rent at assisted-living facilities was reported to have increas

polet [3.4K]

Answer:

a) The 90% confidence interval estimate of the population mean monthly rent is ($3387.63, $3584.37).

b) The 95% confidence interval estimate of the population mean monthly rent is ($3368.5, $3603.5).

c) The 99% confidence interval estimate of the population mean monthly rent is ($3330.66, $3641.34).

d) The confidence level is how sure we are that the interval contains the mean. So, the higher the confidence level, more sure we are that the interval contains the mean. So, as the confidence level is increased, the width of the interval increases, which is reasonable.

Step-by-step explanation:

a) Develop a 90% confidence interval estimate of the population mean monthly rent.

Our sample size is 120.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 120-1 = 119$

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.90}{2} = \frac{0.10}{2} = 0.05$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 119 and 0.05 in the t-distribution table, we have $T = 1.6578$ .

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{650}{\sqrt{120}} = 59.34$

Now, we multiply T and s

$M = T*s = 59.34*1.6578 = 98.37$

The lower end of the interval is the mean subtracted by M. So it is 3486 - 98.37 = $3387.63.

The upper end of the interval is the mean added to M. So it is 3486 + 98.37 = $3584.37.

The 90% confidence interval estimate of the population mean monthly rent is ($3387.63, $3584.37).

b) Develop a 95% confidence interval estimate of the population mean monthly rent.

Now we have that $\alpha = 0.95$

So

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

With 119 and 0.025 in the t-distribution table, we have $T = 1.9801$ .

$M = T*s = 59.34*1.9801 = 117.50$

The lower end of the interval is the mean subtracted by M. So it is 3486 - 117.50 = $3368.5.

The upper end of the interval is the mean added to M. So it is 3486 + 117.50 = $3603.5.

The 95% confidence interval estimate of the population mean monthly rent is ($3368.5, $3603.5).

c) Develop a 99% confidence interval estimate of the population mean monthly rent.

Now we have that $\alpha = 0.99$

So

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.005$

With 119 and 0.025 in the t-distribution table, we have $T = 2.6178$ .

$M = T*s = 59.34*2.6178 = 155.34$

The lower end of the interval is the mean subtracted by M. So it is 3486 - 155.34 = $3330.66.

The upper end of the interval is the mean added to M. So it is 3486 + 155.34 = $3641.34.

The 99% confidence interval estimate of the population mean monthly rent is ($3330.66, $3641.34).

d) What happens to the width of the confidence interval as the confidence level is increased? Does this seem reasonable? Explain.

The confidence level is how sure we are that the interval contains the mean. So, the higher the confidence level, more sure we are that the interval contains the mean. So, as the confidence level is increased, the width of the interval increases, which is reasonable.

4 0

3 years ago

Identify all of the following that are prime number. 2,97,11,27,31,42,59,63,72, and 81

Mademuasel [1]

2, 11, 31, 59 and 97 are all prime numbers.

8 0

3 years ago

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