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2 years ago

Higher order thinking explain why 0.25 x 0.4 has only one decimal place in the product.

1 answer:

6 0

This is a result of the rules of significant figures. These are the digits of the numbers that matter. For operations involving multiplication, the product should have the same significant numbers with the least significant numbers of the given data. In this case, that would be 0.4. Since 0.4 has one significant figure, then the product should be reported with one significant number. That should be 0.1.

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Find the area of the regular pentagon.

IceJOKER [234]

Answer: 172.05

Hope this helps

5 0

2 years ago

What does 25000(1-0.8)^8 equal

Akimi4 [234]

Answer:

0.064

Step-by-step explanation:

25000(1-0.8)^8

= 25000(0.2)^8

= 0.064

7 0

2 years ago

Read 2 more answers

Appreciate the support!

andreyandreev [35.5K]

The volume of a rectangular prism is represented by the following equation:

$V=w*h*l$

Where the variables are for volume, width, height, and length, respectively.

We are given that the area of one end is 16 cm² (units have to be correct when solving these problems, so it's 16 cm², not 16 cm as described in the problem). We know that $A=w*h$

Using this knowledge, we can change the volume equation to our needs.

$V=w*h*l$

$V=(w*h)*l$

$V=A*l$

Note: We know that A is 16 since it's given

$V=16*l$

The volume is 208 cm³ (once again, incorrect units given). Insert this into the equation.

$208=16*l$

Divide both sides of the equation by 16.

$13=l$

The length is 13 cm.

Let me know if you need any clarifications, thanks!

4 0

2 years ago

A hexagonal pyramid that has a slant height of 39 cm and its hexagonal base has a radius of 10√3 cm.

VMariaS [17]

Answer: 225

Step-by-step explanation:

Volume of the pyramid is calculated as 1/3 bh, where b is base and h is height

Given height as 39cm and a base of 10√3cm = 10 x √3, where √3= 1.73; base = 10 x 1.73 = 17.3

Slot the values into the formula:

Volume = 1/3 × 17.3 x 39

= 1/3 × 674.7 = 674.7/3

Volume = 224.9 approximately 225.

I hope this helps.

3 0

2 years ago

This is a pre calculus question that I need help with, serious answer PLEASE and thank you! Will give brainliest.

IRISSAK [1]

The wording of this question is a bit confusing... You can't write a sequence in sigma notation, but rather a series or sum. I think the question is asking you to write the sum of the sequence,

$\dfrac12,\dfrac14,\dfrac18,\ldots,\dfrac1{64}$

which would be

$\dfrac12+\dfrac14+\dfrac18+\cdots+\dfrac1{64}$

in sigma notation.

To do this, notice that the denominator in each term is a power of 2, starting with $2^1=2$ and ending with $2^6=64$ . So in sigma notation, this series is

$\displaystyle\sum_{n=1}^6\frac1{2^n}$

4 0

2 years ago