Question

Find the length of a rectangle with a perimeter of 148 inches and width of 36 inches. inches

Answer 1

Given :-

• Width of rectangle = 36 inches
• Perimeter of rectangle = 148 inches.

To find:-

• Length of rectangle

Solution:-

We know:-

$\bigstar \boxed{ \rm Perimeter \: of \: rectangle = 2(length + width)}$

So:-

$\dashrightarrow \sf 148 = 2(length + 36)$

$\dashrightarrow \sf 148 = 2(length) + 2(36)$

$\dashrightarrow \sf 148 = 2(length) + 2 \times 36$

$\dashrightarrow \sf 148 = 2(length) + 72$

$\dashrightarrow \sf 148 = 2length + 72$

$\dashrightarrow \sf 148 - 72= 2length$

$\dashrightarrow \sf76= 2length$

$\dashrightarrow \sf 2length = 76$

$\dashrightarrow \sf length = \dfrac{76}{2}$

$\dashrightarrow \sf length = \cancel \dfrac{76}{2}$

$\dashrightarrow \bf length = 38 \: inches$

Answer 2

Answer:

Perimeter of rectangle = 2L + 2W

2L + 2 * 36 = 148

2L = 148 - 72

2L = 76

L = 38 inches