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Alex
2 years ago
6

If you get a link, DO NOT CLICK IT OR PASTE IT! its probably an ip finder... if someone gives you a link report the person.

Mathematics
1 answer:
strojnjashka [21]2 years ago
5 0

Answer:

Sweet thx

Step-by-step explanation:

You might be interested in
A group of 7 students was asked, "How many hours did you watch television last week?" Here are their responses. 20,6,17,10,19,15
Burka [1]

Answer: 13.71

Step-by-step explanation:

20+6+17+10+19+15+9=96

96/7=13.71

5 0
3 years ago
The product of a number and ten is twelve more than the product of the number and five-eighths.
ra1l [238]
Let the unknown number be x.

Given,

10 * x = 12 +  \frac{5}{8}  * x

10x = 12 +  \frac{5x}{8}

10x -  \frac{5x}{8} = 12

\frac{(10x*8)-5x}{8} = 12

80x-5x =12*8

75x = 96

x = \frac{96}{75} = 1.28

Hence, the number is 1.28
3 0
3 years ago
Express 0.361 recurring as a fraction.<br> (only the 61 recurs)
Oduvanchick [21]

9514 1404 393

Answer:

  179/495

Step-by-step explanation:

When the repeating decimal starts at the decimal point, the repeating digits can be turned into a fraction by putting them over the same number of 9s. That is, 0.61616161... is equivalent to 61/99.

Here, the repeating part is 1/10 that value, so is 61/990. This is added to the non-repeating part, which is 0.3 = 3/10.

Then the entire decimal is ...

  0.361_61 = 3/10 + 61/990 = (297 +61)/990 = 358/990 = 179/495

7 0
2 years ago
(a) Find a vector parallel to the line of intersection of the planes −4x+2y−z=1 and 3x−2y+2z=1.
valentinak56 [21]

Find the intersection of the two planes. Do this by solving for <em>z</em> in terms of <em>x</em> and <em>y </em>; then solve for <em>y</em> in terms of <em>x</em> ; then again for <em>z</em> but only in terms of <em>x</em>.

-4<em>x</em> + 2<em>y</em> - <em>z</em> = 1   ==>   <em>z</em> = -4<em>x</em> + 2<em>y</em> - 1

3<em>x</em> - 2<em>y</em> + 2<em>z</em> = 1   ==>   <em>z</em> = (1 - 3<em>x</em> + 2<em>y</em>)/2

==>   -4<em>x</em> + 2<em>y</em> - 1 = (1 - 3<em>x</em> + 2<em>y</em>)/2

==>   -8<em>x</em> + 4<em>y</em> - 2 = 1 - 3<em>x</em> + 2<em>y</em>

==>   -5<em>x</em> + 2<em>y</em> = 3

==>   <em>y</em> = (3 + 5<em>x</em>)/2

==>   <em>z</em> = -4<em>x</em> + 2 (3 + 5<em>x</em>)/2 - 1 = <em>x</em> + 2

So if we take <em>x</em> = <em>t</em>, the line of intersection is parameterized by

<em>r</em><em>(t)</em> = ⟨<em>t</em>, (3 + 5<em>t</em> )/2, 2 + <em>t</em>⟩

Just to not have to work with fractions, scale this by a factor of 2, so that

<em>r</em><em>(t)</em> = ⟨2<em>t</em>, 3 + 5<em>t</em>, 4 + 2<em>t</em>⟩

(a) The tangent vector to <em>r</em><em>(t)</em> is parallel to this line, so you can use

<em>v</em> = d<em>r</em>/d<em>t</em> = d/d<em>t</em> ⟨2<em>t</em>, 3 + 5<em>t</em>, 4 + 2<em>t</em>⟩ = ⟨2, 5, 2⟩

or any scalar multiple of this.

(b) (-1, -1, 1) indeed lies in both planes. Plug in <em>x</em> = -1, <em>y</em> = 1, and <em>z</em> = 1 to both plane equations to see this for yourself. We already found the parameterization for the intersection,

<em>r</em><em>(t)</em> = ⟨2<em>t</em>, 3 + 5<em>t</em>, 4 + 2<em>t</em>⟩

3 0
2 years ago
Help me i cant figure this out
scoray [572]
McKenzie's work is correct because on step 3 she added the A and the B correctly.
8 0
3 years ago
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