Fruit:sugar in a ratio 2:3 if 8kg of fruit is used, how much sugar?

1 answer:

6 0

Hey there.

Considering our ratio from fruit to sugar is 2:3, this means we need to make a proportion. I will set this up below;

2:3 = 8:x; x is a variable substitute for our missing sugar value. Let's try to see if 2 divides into 8.
8 / 2 = 4; this means our scale factor of our ratio is 4x larger than the current value, so multiply 2 and 3 by 4 to solve for sugar.

2:3;

2 x 4 = 8; 8:x
3 x 4 = 12; 8:12.

12kg is the missing sugar value in our proportion; therefore, 12kg of sugar is used when 8kg of fruit is used.

I hope this helps!

You might be interested in

Need help finding PT

Fantom [35]

C-26.5 is the answer I think hope it helped

4 0

3 years ago

259 Students go on a field trip. There are 19 vehicles, some vans and some buses.

Sunny_sXe [5.5K]

Answer:

12 vans

7 Buses

Step-by-step explanation:

I tried multiple versions but I finally got it right.

Since the buses can hold 25 students at a time I multiplied it by 7.

7 x 25 = 175

Then you'll need to find the remainder.

259-175 = 84

This number would be used to find the students going in the van

84/7= 12

So in total there would be 12 vans

and 7 buses

I hope this helps

5 0

3 years ago

Solve for u.<br> 3u^2–19u–14=0

Oksanka [162]

3u^2-19u-14=0
9u-19u-14=0
-10u-14=0
+10u +10u
-14=10u
/10 /10
u=-0.14
i think
hope this helps

8 0

3 years ago

Civil engineer wants to estimate the maximum number of cars that can safely travel on a particular road at a given speed. He ass

pychu [463]

$N(s)= \frac{89s}{14+14( \frac{s}{17})^2 }
\\
\\N'(s)= (\frac{89s}{14+14( \frac{s}{17})^2 } )'= \frac{89\times 14(1+( \frac{s}{17})^2)-89s\times \frac{28}{17} }{14^2(1+( \frac{s}{17})^2)} 
\\
\\N'(s)=0
\\
\\89\times 14(1+( \frac{s}{17})^2)-89s\times \frac{28}{17}=0
\\
\\1+( \frac{s}{17})^2- \frac{2s}{17} =0
\\
\\289+s^2-34s=0
\\
\\s^2-34s+289=0
\\
\\(s-17)^2=0
\\
\\s=17
$