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Rina8888 [55]
3 years ago
11

Solve the following equations. log6(x) = 1

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
7 0

Answer:

x = 6

Step-by-step explanation:

Given:

log₆(x) = 1

Now,

From the properties of log

logₓ (z)= \frac{\log(z)}{\log(x)}  (where the base of the log is equal for both numerator and the denominator)

also,

log(xⁿ) = n × log(x)

thus,

using the above properties, we can deduce the results as:

logₓ(y) = n is equivalent to y = xⁿ

therefore,

the given equation can be deduced as:

log₆(x) = 1

into,

x = 6¹

or

x = 6

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Ksivusya [100]
Let <span>simplify the equations a^7xy-a^6y-a^5x=a^4(b^4-1) and (a^mx-a^n)(a^py-a^2)=a^4b^4:
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<span>1) a^7xy-a^6y-a^5x+a^4=a^4b^4
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<span>and
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<span>2) a^{m+p}xy-a^{n+p}y-a^{m+2}x+a^{n+2}=a^4b^4.
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3 years ago
What is the slope intercept form of 3x+1=7-4y
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Answer:

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b.     3/5                                  3/8

c.     4/5                                  4/7

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