Divide both sides by 7.
n must be less than or equal to 3. n can be 3 or any number under 3.
For example, n can be 1, 2, 3.
Solve the following equations. log6(x) = 1
1 answer:
Answer:
x = 6
Step-by-step explanation:
Given:
log₆(x) = 1
Now,
From the properties of log
logₓ (z)= (where the base of the log is equal for both numerator and the denominator)
also,
log(xⁿ) = n × log(x)
thus,
using the above properties, we can deduce the results as:
logₓ(y) = n is equivalent to y = xⁿ
therefore,
the given equation can be deduced as:
log₆(x) = 1
into,
x = 6¹
or
x = 6
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Divide both sides by 7.
n must be less than or equal to 3. n can be 3 or any number under 3.
For example, n can be 1, 2, 3.
Answer:
1.60
Step-by-step explanation:
Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.
i.e Area =
So that,
for the inner part of the pipe,
r =
=
= 2.5 feet
Area of the inner part of the pipe =
= 3.14 x
= 19.625
Are of the inner part of the pipe is 19.63 .
Total diameter of the pipe = 5 + 0.2
= 5.2 feet
r =
= 2.6 feet
Area of the pipe =
= 3.14 x
= 21.2264
Area of the pipe is 21.23 .
Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe
= 21.2264 - 19.625
= 1.6014
The cross sectional area of the cement pipe is 1.60 .