Answer:
$30.4
Step-by-step explanation:
fist we figure out what 5% of 32 is which is 1.6 then we subtract it from the total cost 32 - 1.6 = 30.4
Nter any function to compute the domain<span> and </span>range<span>. Specify a restriction on the independent variable. Compute </span>domain<span> and </span>range<span> for functions of several variables. ... </span>domain<span> and </span>range<span> of (</span>x^2+1)/(x^4-1) ...domain<span> of </span>f(x,y) = log(1-(x^2+y^2<span>)).</span>find<span> the </span>range<span> of </span>f(x<span>) = </span>x2+2x+1/x2-8x+12<span>. ... Write </span>domain<span> and </span>range<span> of greatest integer function. hopes this helps u
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A is not allowed, because it does not use the elimination method correctly.
Answer:




Step-by-step explanation:
Given







Solving (a): A) P(cable TV only).
First, we calculate n(cable TV only)
This is calculated as:



The probability is:



Solving (b): P(Internet | cable TV).
This is calculated as:




Solving (c): P(exactly 2 services).
This is calculated as:




Solving (d): P(Internet and cable TV only).
This is calculated as:



