Question

What is the standard form equation of the line shown below? Graph of a line going through negative 3, negative 1 and 3, 2 y + 1 = one half(x + 3) y = one halfx + five halves −x + 2y = 1 x − 2y = −1

Answer 1

(-3,-1)(3,2)
slope = (2 - (-1) / (3 - (-3) = (2 + 1) / (3 + 3) = 3/6 = 1/2

y = mx + b
slope(m) = 1/2
use either of ur points...(3,2)...x = 3 and y = 2
now sub and find b, the y int
2 = 1/2(3) + b
2 = 3/2 + b
2 - 3/2 = b
4/2 - 3/2 = b
1/2 = b

so ur equation is : y = 1/2x + 1/2...but we need it in standard form of Ax + By = C

y = 1/2x + 1/2....subtract 1/2x from both sides
-1/2x + y = 1/2 ...multiply both sides by -2
x - 2y = -1 <== standard form