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3 years ago

7

Please help i was stuck on this problem for 20 minutes now :(

1 answer:

Mila [183]3 years ago

3 0

Answer:

Step-by-step explanation:

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AB=4, AE=6, ED=9, Find AC=

LiRa [457]

Ab/ac = ae/ad = be/cd

4/ac = 6/15

6 ac = 60
ac = 60/6 = 10

ac = 10

6 0

3 years ago

Pleasee helpp againnnn loo

densk [106]

The second answer 5(2,5d)

5 0

3 years ago

The distance of planet Mercury from the Sun is approximately 5.8 ⋅ 10^7 kilometers, and the distance of planet Venus from the Su

ziro4ka [17]

Distance(Mercury, Sun) = 5.8 x 10^7
distance(Venus, Sun) = 1.1 x 10^8

distance(Venus, Mars) = 1.1 x 10^8 - 5.8 x 10^7

The subtraction is a little easier if you borrow a power of 10 from the 10^8, multiplying 1.1 by 10.

$\rm 11.0\times10^7-5.8\times10^7$

simply subtract 5.8 from 11.0.
This gives us a result of 5.2 x 10^7.

Hope that makes sense!

8 0

3 years ago

Read 2 more answers

Simplify 8 - {X - (5 + x)).<br> 3<br> 013<br> -2x + 3<br> -2x + 13

Basile [38]

Answer:

13

Step-by-step explanation:

8 0

3 years ago

If sine theta equals three over four, what are the values of cos θ and tan θ?

ankoles [38]

Answer:

Part 1) $cos(\theta)=(+/-)\frac{\sqrt{7}}{4}$

cosine theta equals plus or minus square root of seven over 4

Part 2) $tan(\theta)=(+/-)\frac{3}{\sqrt{7}}$

tangent theta equals plus or minus three over square root of seven

or

$tan(\theta)=(+/-)3\frac{\sqrt{7}}{7}$

tangent theta equals plus or minus three times square root of seven over seven

Step-by-step explanation:

we have that

The sine of angle theta is equal to

$sin(\theta)=\frac{3}{4}$

Is positive

therefore

The angle theta lie on the I Quadrant or in the II Quadrant

Part 1) Find the value of the cosine of angle theta

Remember that

$sin^{2} (\theta)+cos^{2} (\theta)=1$

we have

$sin(\theta)=\frac{3}{4}$

substitute and solve for cosine of angle theta

$(\frac{3}{4})^{2}+cos^{2} (\theta)=1$

$cos^{2} (\theta)=1-(\frac{3}{4})^{2}$

$cos^{2} (\theta)=1-\frac{9}{16}$

$cos^{2} (\theta)=\frac{7}{16}$

$cos(\theta)=(+/-)\frac{\sqrt{7}}{4}$

cosine theta equals plus or minus square root of seven over 4

Part 2) Find the value of tangent of angle theta

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=\frac{3}{4}$

$cos(\theta)=(+/-)\frac{\sqrt{7}}{4}$

substitute

$tan(\theta)=\frac{\frac{3}{4}}{(+/-)\frac{\sqrt{7}}{4}}$

$tan(\theta)=(+/-)\frac{3}{\sqrt{7}}$

tangent theta equals plus or minus three over square root of seven

Simplify

$tan(\theta)=(+/-)3\frac{\sqrt{7}}{7}$

tangent theta equals plus or minus three times square root of seven over seven

4 0

3 years ago