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Oksana_A [137]
4 years ago
8

If the fifth and eighth terms of an arithmetic sequence are minus 9 and minus 21, respectively, what are the first four terms of

the sequence?
Mathematics
1 answer:
Reil [10]4 years ago
4 0
One way to do this problem is to determine the common difference.  If the 5th and 8th terms are -9 and -21, we can do this by subtracting -9 from -21:

-21-(-9) = -12.  The 5th and 8th terms are not consecutive, so we have to think in terms of (8-5), or 3, times the common difference to get from -9 to -21.

Note that -12 divided by 3 is -4.  Thus, the common difference is -4.

Check:  -9 - 4 = -13; -13 - 4 = -17; -17 - 4 = -21 (which is correct).

We know that the 5th term is -9.  To find the 4th term, work backwards:  subtract (-4) from -9, which produces -9+4=-5.

The fourth term is -5.  Subtracting -4 from this (which is the same as adding 4 to this -5) produces the third term; it is -1.  Can you now find the 2nd and 1st terms using the same approach?

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Answer:

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Step-by-step explanation:

We are given three equations to solve. First, let's solve the equations for x.

<u>Equation 1</u>

<u />\displaystyle{6x+8=7x+13}\\\\7x + 13 = 6x + 8\\\\x + 13 = 8\\\\\bold{x = -5}<u />

Therefore, we determined that for the first equation, x = -5. We can check our solution by substituting it back into the original equation.

\displaystyle{6(-5)+8=7(-5)+13}\\\\-30 + 8 = -35 + 13\\\\-22 = -22 \ \checkmark

Since we got a true statement, there are no other values of x for which we get a true statement. Let's test this with the opposite value: positive 5.

6(5)+8=7(5)+13\\\\30 + 8 = 35 + 13\\\\38 = 48 \ \text{X}

Therefore, for Equation 1, there is exactly one solution.

<u>Equation 2</u>

<u />6 x + 8 = 2 ( 3 x + 4 )\\\\6x + 8 = 6x + 8\\\\0 + 8 = 8\\\\8 = 8 \ \checkmark<u />

We get a true statement by solving for x (which ends up canceling out of the equation entirely). Therefore, we can check <u>any value</u> in place of x to see if we get a true statement. For this instance, I will use -3.

6(-3) + 8 = 2 ( 3(-3) + 4 )\\\\-18 + 8 = 2(-9+4)\\\\-18 + 8 = 2(-5)\\\\-18 + 8 = -10\\\\-18 = -18 \ \checkmark

We still get a true statement, so Equation 2 has infinitely many solutions.

<u>Equation 3</u>

<u />6 x + 8 = 6 x + 13\\\\0 + 8 = 13\\\\8 \neq 13<u />

We get a false statement. Therefore, Equation 3 has no solution.

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