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Oksana_A [137]
3 years ago
8

If the fifth and eighth terms of an arithmetic sequence are minus 9 and minus 21, respectively, what are the first four terms of

the sequence?
Mathematics
1 answer:
Reil [10]3 years ago
4 0
One way to do this problem is to determine the common difference.  If the 5th and 8th terms are -9 and -21, we can do this by subtracting -9 from -21:

-21-(-9) = -12.  The 5th and 8th terms are not consecutive, so we have to think in terms of (8-5), or 3, times the common difference to get from -9 to -21.

Note that -12 divided by 3 is -4.  Thus, the common difference is -4.

Check:  -9 - 4 = -13; -13 - 4 = -17; -17 - 4 = -21 (which is correct).

We know that the 5th term is -9.  To find the 4th term, work backwards:  subtract (-4) from -9, which produces -9+4=-5.

The fourth term is -5.  Subtracting -4 from this (which is the same as adding 4 to this -5) produces the third term; it is -1.  Can you now find the 2nd and 1st terms using the same approach?

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DanielleElmas [232]
Total = Principal * e^(rate*years)
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Total = 1,600 * e(.046*4)
Total = 1,600 * 2.71828182828459^(.184)
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Source:
http://www.1728.org/rate2.htm





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If a/b = 4/3 and b/c = 2/3, what is a,b, and c?
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Answer:

.

Step-by-step explanation:

\frac{a}{b}  =  \frac{4}{3}

\frac{b}{c}  =  \frac{2}{3}

to give b from both equation the same value

\frac{a}{b}  =  \frac{4}{3}  \times   \frac{2}{2}  =  \frac{8}{6}

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7 0
3 years ago
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