Answer:
Step-by-step explanation:
you can solve for the fractions first, but you have to give them a common denominator
which is in simplest form
then solve for the whole numbers
3-2=1
therefore, the answer is
Answer:
32 pound but I dunno what that is in american dollars
Not sure but It should be -4/1
<u>Answer:
</u>
Required expression for one-eight of the sum of a number and three is 
<u>Solution:
</u>
Given that unknown value is represented by variable x.
Need to create algebraic expression for One-eight of the sum of a number and three.
Let’s first find one eight of the number that is 1/8th of x = 
Now on adding three we get
Hence required expression for one-eight of the sum of a number and three is
// Input value is usernum.
// This code snippet sums 1 + 3 + 5 + ... + usernum
// The answer is stored in the variable summedvalue.
N = (int) (usernum+1)/2; // maximum number of integers to be summed
int *v = malloc(N*sizeof(int)); // allocate storage for array v
// Calculate the number of loop counts and assign array v..
count = 0;
k = 1;
while (1) {
if (k>usernum) { // do not extend v beyond usernum
break;
}
v(count) = k; // assign an odd integer to v, including usenum
count++;
k += 2; // k is an odd number
if k>usernum { // handle usernum as odd or even
k = usernum;
}
}
n = count; // the size of array v.
// Calculate the sum in a for loop
summedvalue = 0; // initialize summedvalue
for (i=0; i<=n; i++) {
summedvalue += v(i);
}
