Answer:
Correct answer: c = 29 m, a = 21 m and b = 20 m
Step-by-step explanation:
Given:
a = b + 1 longer leg a
c = b + 9 hypotenuse c
To solve this problem, we will use Pythagoras' theorem
c² = a² + b²
(b + 9)² = (b + 1)² + b²
b² + 18 b + 81 = b² + 2 b + 1 + b²
2 b² - b² + 2 b - 18 b + 1 - 81 = 0
b² - 16 b - 80 = 0 we will factorize this equation
⇒ b² - 20 b + 4 b - 80 = b (b - 20) + 4 ( b - 20) = (b - 20) · (b + 4) = 0
(b - 20) · (b + 4) = 0 ⇒ b = 20 or b = - 4 false
we accepted b = 20 m
c = b + 9 = 20 + 9 = 29 m
c = 29 m
a = b + 1 = 20 + 1 = 21 m
a = 21 m
God is with you!!!
Answer:
The required probability is 0.048
Step-by-step explanation:
Consider the provided information.
Out of 52 card we need to select only 2.
Therefore the sample space is: 
One card is Ace. The number of Ace are 4 and we need to select one of them.
This can be written as: 
The second card can be Ten or a Jack or a Queen or a King.
There are 4 Ten, 4 jack, 4 Queen, and 4 king in a deck and we need to select only 1 out of them.
So we can say that we need to select 1 card out of 16.
This can be written as: 
Thus, the probability that one of the cards is an ace and the other one is either a ten, a jack, a queen or a king is:

Hence, the required probability is 0.048
Answer:
Vertex Distance to Vertex Distance to
A 3.6 AEF 3.6
B 2.2 BEF 2.2
C 2.0 CEF 2.0
D 3.4 DEF 3.4
Step-by-step explanation:
One way you could solve this is to just multiply the top and bottom out so that you get 9/81, reducing it by 9/9 to get 1/9 or option C.
Another way would be to do

since dividing numbers with exponents would be subtracting the bottom exponent from the top exponent, provided that the base number (in this case 3) is the same for both. For this method, you would get

, which is equal to 1/9 or .1 repeating, the same answer that you'd get with the first method.