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victus00 [196]
3 years ago
15

What is a constant interval and how does it appear on a graph?

Mathematics
2 answers:
Novay_Z [31]3 years ago
8 0
<span>Pre-Calculus - Identify where a function is increasing decreasing or constant from the graph
</span>
Example: The graph<span> shown above is decreasing from the point (3,4) to the point (5,-5), described as decreasing when 3 < x < 5. Using interval notation, it is described as decreasing on the interval (3,5). </span>Constant<span>: A function is </span>constant<span>, if as x increases (reading from left to right), y stays the same.

watch this video
</span>
8090 [49]3 years ago
3 0
A function whose value does not vary, regardless of the input.
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What is the percent increase from 3/8 to 7/8? HELP PLEASE I'VE BEEN STUCK ON THIS FOREVERRRRRRRR
iogann1982 [59]
3/8th = 0.375 
<span>7/8th = 0.875 
</span><span>The increase is over so, 1.000 would be .500 = 50% 

Good luck with your studies. Hope this helps~!
</span>

3 0
3 years ago
Read 2 more answers
20x+3=17 help please
jeyben [28]
The objective is to get the variable (x) alone. To do this start be subtracting 3. What you do to one side you have to do to the other so you have to subtract three from the other side of the equal sign as well. So now you have:
20x= 17-3 subtract the 3 to get 20x=14
Now because the 20 is attached to the x In order to get the x alone you have to divide by 20:
20x/20. =14/20 divide 14 by 20

X=.7 or x=7/10
5 0
3 years ago
Read 2 more answers
Find the solutions to the following linear-quadratic systems algebraically. Select the ordered pair that is one of the correct s
Ghella [55]

Answer:

(-2, 6)

Step-by-step explanation:

we have

y=x^{2} +3x+8 ----> equation A

y=2x+10 ----> equation B

equate equation A and equation B

x^{2} +3x+8=2x+10

x^{2} +3x+8-2x-10=0

x^{2} +x-2=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^{2} +x-2=0

so

a=1\\b=1\\c=-2

substitute in the formula

x=\frac{-1\pm\sqrt{1^{2}-4(1)(-2)}} {2(1)}

x=\frac{-1\pm\sqrt{9}} {2}

x=\frac{-1\pm3} {2}

x=\frac{-1+3} {2}=1

x=\frac{-1-3} {2}=-2

Find the values of y

For x=1

y=2(1)+10=12

For x=-2

y=2(-2)+10=6

therefore

The solutions are (1,12) and (-2,6)

3 0
3 years ago
Y= 5x -3 what does y=
irga5000 [103]

Answer:

15

Step-by-step explanation:

6 0
3 years ago
Divide -2x3-5x2+4x+2 by x+2
lilavasa [31]
It would be -26

Its very easy But you will get better =)

4 0
3 years ago
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