Answer:
The function has at least 1 zero within the interval [-2,5].
Step-by-step explanation:
The intermediate value theorem states that, for a function continuous in a certain interval ![[a,b]](https://tex.z-dn.net/?f=%5Ba%2Cb%5D)
, then the function takes any value between 
and 
at some point within that interval.
This theorem has an important consequence:
If a function 
is continuous in an interval [a,b], and the sign of the function changes at the extreme points of the interval:
(or viceversa)
Then the function f(x) has at least one zero within the interval [a,b].
We can apply the theorem to this case. In fact, here we have a function f(x) continuous within the interval
[-2,5]
And we also know that the function changes sign at the extreme points of the interval:
Therefore, the function has at least 1 zero within the interval [-2,5], so there is at least one point x' within this interval such that
Answer:
12
Step-by-step explanation:
1. You con solve the quadratic equation x^2+20x+100=50<span> by following the proccedure below:
2. Pass the number 50 from the right member to the left member. Then you obtain:
x^2+20x+100-50=0
</span><span> x^2+20x+50=0
</span><span>
3. Then, you must apply the quadratic equation, which is:
x=(-b±√(b^2-4ac))/2a
</span><span>x^2+20x+50=0
</span><span>
a=1
b=20
c=50
4. Therefore, when you substitute the values into the quadratic equation and simplify ir, you obtain that the result is:
-10</span>±5√2 (It is the last option).
This is the concept of area of solid materials, we are required to calculate the total area of horsehide that is required to cover 100 balls with each having a circumference of 9 in.
The area of hide required will be given by:
area=(area of each ball)*(total number of balls)
area of each ball is given by:
SA=4πr^2
given that the circumference is 9in, we are required to find the radius of the ball
Circumference, c=2πr
thus;
9=2πr
r=9/(2π)
r=1.4 in
Therefore the surface area will be:
SA=4π*1.4^2=24.6 in^2
Therefore the area of horsehide required to cover 100 balls will be:
Area=24.6*100=2,460 in^2.
