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Butoxors [25]
3 years ago
11

Felicity's dog eats two cups of dog food per day. Felicity's dog eats at least one-quarter cup more than one-half of the amount

Martin's dog eats. If the amount of food that Martin's dog eats is represented by using m, which inequality represents the situation?
Mathematics
2 answers:
Jlenok [28]3 years ago
7 0

Answer: A

Step-by-step explanation:

The answer is A i got this correct

(The person above me is correct!)

cupoosta [38]3 years ago
4 0

Answer:

2 > \frac{1}{2} m + \frac{1}{4}  

Step-by-step explanation:

Given:

  • Felicity's dog eats two cups of dog food per day :2

If the amount of food that Martin's dog eats is represented by using m

Felicity's dog eats at least one-quarter cup more than one-half of the amount Martin's dog eats: \frac{1}{2} m + \frac{1}{4}

So we have the inequality represents the situation is:

2 > \frac{1}{2} m + \frac{1}{4}  

You might be interested in
How do i solve x/8=3/4
dusya [7]

Answer:

Quite simply. The answer is X=6

Since you have a full fraction, you can find a common denominator in both fractions and multiply. (The common denominator would be 8, so you would multiply 4 by 2 to get 8. Do the same thing to the top, do multiply 3 by 2 to get 6). Now the fraction is 6/8, and since it's equal to incomplete fraction, you know X is 6.

5 0
3 years ago
1948 Olympics
mash [69]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

               ⬆                ⬆                 ⬆

         Low IQR      Median       High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR  is average of 59.3 and 59.6 =  59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

                    ⬆                  ⬆                      ⬆

             Low IQR         Median          High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

Read more on Brainly.com - brainly.com/question/14915771#readmore

8 0
4 years ago
Reflection across y=x​
alexdok [17]
C= (-2,3) B=(-3,0) D=(-3,4) would be the reflection across the axis
5 0
3 years ago
Help me asap please & thank you.
vaieri [72.5K]
Howwwww.....................
6 0
3 years ago
Please answer fast, dhehdhhd
Readme [11.4K]

I believe the answer is 142 degrees.

38 degrees and 7 are adjacent, meaning adding them up will get you 180 degrees. 180-38=142, so 7 is 142.

Number 7 and 5 are corresponding, so they are equal.

This means that 5 is 142 degrees.

(I think)

4 0
3 years ago
Read 2 more answers
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