I suppose that when you write "log^6" , you want to say log₆
Change of base formula:
loga b=logc b / logc a
log₆ 120=ln 120 / ln 6=2.67
Answer: log₆ 120=2.67
The answer for this is 3(k+6)^2 u need to factor this so use magic X
Y’’(x)= 6x + 1
y’(x)= 3x^2 + x + 2
y(x)= x^3 + 1/2x^2 + 2x + 5
Answer:
15.094 %
Step-by-step explanation:
[(122 - 106) /106] 100
(16/106) 100
(0.15094)x100
15.094