<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%5Calpha-1%5Cfrac%7B1%7D%7B5%7D%3D2%5Cfrac%7B3%7D%7B4%7D" id="TexFormula1

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3 years ago

" title="\frac{3}{4}\alpha-1\frac{1}{5}=2\frac{3}{4}" alt="\frac{3}{4}\alpha-1\frac{1}{5}=2\frac{3}{4}" align="absmiddle" class="latex-formula">

1 answer:

5 0

I DONT KNOW LOL PLS STOP CHEATING

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nikklg [1K]

Hey there!

Firstly, you have to $\bold{simplify}$ each of the sides of your equation
$\bold{6-2p-p+9\downarrow}$
$\bold{6+(-2p)=p+9\downarrow}$
$\rightarrow\bold{-2p+6=p+9}$
Now that you have that portion out of the way, we could move on to our second step... which is to $\bold{subtract}$ by the value of $\bold{p}$ on each of your sides
$\bold{-2p+6-p-p+9-p\downarrow}$
$\rightarrow\bold{-3p+6-9}$ (you get this because we solve the particular equation we added above)
Thirdly, you have to $\bold{subtract}$ by the number $\bold{6}$ on each of your sides
$\bold{-3p+6-6=9-6\downarrow}$
$\bold{Cancel:6-6}$ because it equals to $\bold{0}$
$\bold{Keep:9-6}$ because it brings us closer and closer to the answer of $\bold{p}$
Fourthly, we have to $\bold{divide}$ by the number $\bold{-3}$ on each of your sides
$\bold{\frac{-3p}{-3}=\frac{3}{-3}}$
$\boxed{\boxed{\bold{Answer:p=-1}}}$ $\checkmark$