No sorry:( hope someone helps
R = 230 m
v = 17 m/s
Formula: |Ac| = v^2 / r
Point A
|Ac| = v^2 / r = (17m/s)^2 / (230m) = 1.257 m/s^2
Components:
cos(25) = - [ x-component / |Ac| ] => x-component = -|Ac|*cos(25)
sin(25) = - [y-component / |Ac| ] => y-component = - |Ac|*sin(25)
x-component = - 1.256 * cos(25) m/s^2 = - 1.139 m/s^2
y-component = -1.256 * sin (25) m/s^2 = - 0.531 m/s^2
Point B
|Ac| = 1.256
x-component = - 1.256 cos(58) = - 0.666 m/s^2
y-component = + 1.256 sin(58) = + 1.065 m/s^2
Answer:
236 cm^2
Step-by-step explanation:
Formula
Area = sector angle/360 * pi * r^2
Givens
Sector angle = 120
r = 15
Solution
Area = 120/360 * 3.14 * 15 * 15
Area = 1/3 * 3.14 * 225
Area = 235.5
Area = 236 cm^2
Answer for problem 46 is choice A
Answer for problem 47 is choice B
Answer for problem 48 is choice E
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Work Shown
Problem 46
Equation 1: 3x+y = 17
Equation 2: x+3y = -1
Add equation 1 to equation 2 to get 4x+4y = 16. Divide every term by 4 to get x+y = 4. Then finally multiply both sides by 3 to get 3x+3y = 12
That shows why the answer is choice A
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Problem 47)
If y hours pass by, then y-(2/3)y=y/3 is the time value (2/3)y hours ago
So,
Distance = rate*time
d = r*t
d = x*(y/3)
d = (xy)/3
That's why the answer is choice B
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Problem 48)
Let L1,L2,L3 be the three lists where
L1 = {a1,a2,a3,...,ak} there are k scores here
L2 = {a1,a2,...,a10} there are 10 scores here
L3 = {a11,a12,...,ak} the remaining k-10 scores
S(L1) = sum of the scores in list L1
M(L1) = mean of L1 = 20 = S(L1)/k
M(L2) = mean of L2 = 15 = S(L2)/10
S(L1) = 20k
S(L2) = 150
S(L1) = S(L2)+S(L3)
M(L1) = [S(L2)+S(L3)]/k
20 = [150+S(L3)]/k
20k = 150+S(L3)
S(L3) = 20k-150
M(L3) = [S(L3)]/(k-10)
M(L3) = (20k-150)/(k-10)
So that shows why the answer is choice E
