You're being asked to divide 6x^3 - 19x^2 + 16x - 4 by x - 2.
Try using synthetic division, if you know it:
_______________
2 / 6 -19 16 -4
12 -14 4
--------------------------
6 -7 2 0
6, -7 and 2 are the coefficients of the quotient. The quotient (answer to this question) is
6x^2 - 7x + 2
Answer:
Step-by-step explanation:
<u>All the points that are 7 units from the origin are on the circle:</u>
<u>The maximum and minimum values of x obtained when y = 0:</u>
So
<u>The points are:</u>
Wow this question is very difficult,hold up
Answer:

Step-by-step explanation:
step 1
Find the measure of the arc DC
we know that
The inscribed angle measures half of the arc comprising
![m\angle DBC=\frac{1}{2}[arc\ DC]](https://tex.z-dn.net/?f=m%5Cangle%20DBC%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20DC%5D)
substitute the values
![60\°=\frac{1}{2}[arc\ DC]](https://tex.z-dn.net/?f=60%5C%C2%B0%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20DC%5D)


step 2
Find the measure of arc BC
we know that
----> because the diameter BD divide the circle into two equal parts
step 3
Find the measure of angle BDC
we know that
The inscribed angle measures half of the arc comprising
![m\angle BDC=\frac{1}{2}[arc\ BC]](https://tex.z-dn.net/?f=m%5Cangle%20BDC%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20BC%5D)
substitute the values
![m\angle BDC=\frac{1}{2}[60\°]](https://tex.z-dn.net/?f=m%5Cangle%20BDC%3D%5Cfrac%7B1%7D%7B2%7D%5B60%5C%C2%B0%5D)

therefore
The triangle DBC is a right triangle ---> 60°-30°-90°
step 4
Find the measure of BC
we know that
In the right triangle DBC


substitute the values

5 + 4x
I think that’s right