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Tresset [83]
3 years ago
13

How to do 55 is increased to 90

Mathematics
1 answer:
GenaCL600 [577]3 years ago
3 0
90 minus 55 is 35, I am trying to answer the best I can. I hope that is that you asked for! :)
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What is the value of f(x) = 2(0.75)^x when x=3
Nadusha1986 [10]
<span>f(x) = 2(0.75)^x 
at x = 3
>> </span>f(3) = 2(0.75)^3 
>> f(3) = <u>0.84375</u>
6 0
3 years ago
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Find the value of x in the equation below. 2.7+x=11.7
forsale [732]

Answer:

the answer is 9

Step-by-step explanation:

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3 years ago
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Find x<br> 5[x^2]+5[x]-x^2-x=2004
a_sh-v [17]

The answer is either x=\frac{-1}{2}+\frac{1}{2}\sqrt{2005}\\ or x=\frac{-1}{2}+\frac{-1}{2}\sqrt{2005}

To solve: Let's solve your equation step-by-step.

5x2+5x−x2−x=2004

Step 1: Simplify both sides of the equation.

4x2+4x=2004

Step 2: Subtract 2004 from both sides.

4x2+4x−2004=2004−2004

4x2+4x−2004=0

Step 3: Use quadratic formula with a=4, b=4, c=-2004.

x= −b±√b2−4ac /2a

x= −4±√32080 /8

x=\frac{-1}{2}+\frac{1}{2}\sqrt{2005}\\ or x=\frac{-1}{2}+\frac{-1}{2}\sqrt{2005}

4 0
3 years ago
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Please answer it quickly the question is below!!! 40 points!!!!
andrew-mc [135]

Answer:

187.5 ft

Step-by-step explanation:

50 ft x 3.75 = 187.5

8 0
3 years ago
In the problem below, AB, CD, and EF are two-digit numbers, where A, B, C, D, E and F represent distinct digits from 1 to 9. Is
Oksi-84 [34.3K]

Answer:

<em>When both the conditions hold true, F is prime.</em>

Step-by-step explanation:

AB, CD, and EF are two-digit numbers, where A, B, C, D, E and F represent distinct digits from 1 to 9.

  AB

+ CD

--------

  EF

1st condition, B and D are consecutive.

Adding B and D gives us F.

Possible values can be (F being the unit value after adding not considering the carry over):

B + D = F

1+2=3

2+3=5

3+4=7

4+5=9

5+6=1

6+7=3

7+8=5

8+9=7

Here F is not prime (because 9 is not prime).

Now, let us consider the 2nd condition as well.

i.e. C = 8

For the following

  AB

+ CD

--------

  EF

C is 8 then A must be 1 because any value other than 1 for A will make the sum of A and C greater than 9 and there will be a carry which is not the case here.

So, E = 8 + 1 = 9

Now, B  and D are consecutive and can not be 1, 8 or 9.

So, possible values are:

B + D = F

2 + 3 = 5

3 + 4 = 7

Here F is prime.

So, when both the conditions hold true, F is prime.

3 0
3 years ago
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